Question
∫dx(x−3)(4/5)(x+1)6/5=
Answer: Option B
:
B
I=∫dx(x−3)4/5(x+1)6/5Putt=x−3x+1dt=4(x+1)2dx.I=14∫dtt4/5=14(t−4/5+1−4/5+1)=54t1/5=54(x−3x+1)1/5
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:
B
I=∫dx(x−3)4/5(x+1)6/5Putt=x−3x+1dt=4(x+1)2dx.I=14∫dtt4/5=14(t−4/5+1−4/5+1)=54t1/5=54(x−3x+1)1/5
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