Question
∫100sec2(3x+6)dx
Answer: Option D
:
D
I=∫100sec2(3x+6)dx
Let 3x+6=u
⇒3dx=du⇒dx=du3
I=∫sec2udu3
=13tan(u)+c
I=13tan(3x+6)100
13[tan36−tan6]
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:
D
I=∫100sec2(3x+6)dx
Let 3x+6=u
⇒3dx=du⇒dx=du3
I=∫sec2udu3
=13tan(u)+c
I=13tan(3x+6)100
13[tan36−tan6]
Was this answer helpful ?
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