Question
Find the integral of the given function w.r.t x
y=cos(8x+6)+cosec2(7x+5)+6sec x tan x
y=cos(8x+6)+cosec2(7x+5)+6sec x tan x
Answer: Option C
:
C
Let u=8x+6,dudx=8⇒dx=du8
t=7x+5,dtdx=7⇒dx=dt7
∫ydx=∫cosudu8+∫cosec2tdt7+6∫secxtanxdx
= sinu8+(−cott)7+6secx+c
= sin(8x+6)8−cot(7x+5)7+6secx+c
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:
C
Let u=8x+6,dudx=8⇒dx=du8
t=7x+5,dtdx=7⇒dx=dt7
∫ydx=∫cosudu8+∫cosec2tdt7+6∫secxtanxdx
= sinu8+(−cott)7+6secx+c
= sin(8x+6)8−cot(7x+5)7+6secx+c
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