Question
(aa+x)12 + (aa−x)12 =
Answer: Option A
:
A
(a+xa)−12 + (a−xa)−12 =(1+xa)−12+(1−xa)−12
=[1 + (- 12)( xa) + (−12)(−32)2.1(xa)2 + ........]
+ [1+(−12)(−xa)+(−12)(32)2.1(−xa)2+........]
= 2 + 3x24a2 + ......
Here odd terms cancel each other.
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:
A
(a+xa)−12 + (a−xa)−12 =(1+xa)−12+(1−xa)−12
=[1 + (- 12)( xa) + (−12)(−32)2.1(xa)2 + ........]
+ [1+(−12)(−xa)+(−12)(32)2.1(−xa)2+........]
= 2 + 3x24a2 + ......
Here odd terms cancel each other.
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