Question
C0−C1+C2−C3+........+(−1)nCn is equal to
Answer: Option C
:
C
We know that
(1+x)n=nC0+nC1x+nC2x2+......+nCnxn
Putting x = -1, we get
(1−1)n =nC0-nC1+nC2- .......(−1)n nCn
Therefore C0−C1+C2−C3+......(−1)nCn = 0
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:
C
We know that
(1+x)n=nC0+nC1x+nC2x2+......+nCnxn
Putting x = -1, we get
(1−1)n =nC0-nC1+nC2- .......(−1)n nCn
Therefore C0−C1+C2−C3+......(−1)nCn = 0
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