Question
(4pq+3q)2 − (4pq−3q)2= ____________.
Answer: Option C
:
C
(4pq+3q)2−(4pq−3q)2
We have:
(a+b)2=a2+2ab+b2(a−b)2=a2−2ab+b2
So,(4pq+3q)2−(4pq−3q)2
=[(4pq)2+(3q)2+2(4pq)(3q)]−[(4pq)2+(3q)2−2(4pq)(3q)]
=24pq2+24pq2
=48pq2
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:
C
(4pq+3q)2−(4pq−3q)2
We have:
(a+b)2=a2+2ab+b2(a−b)2=a2−2ab+b2
So,(4pq+3q)2−(4pq−3q)2
=[(4pq)2+(3q)2+2(4pq)(3q)]−[(4pq)2+(3q)2−2(4pq)(3q)]
=24pq2+24pq2
=48pq2
Was this answer helpful ?
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