Question
Sandeep wants to buy 5 chocolates of Rs 10 each. He has to pay Rs 20 for parking also. If the price of chocolate is increased by Rs x, he decides to buy y less chocolates and he has to pay Rs z less for the parking. Write the arithmatic expression of the money spent by Sandeep. [2 MARKS]
Answer:
:
Concept: 1Mark
Application: 1 Mark
Price of chocolate = (10 + x)
No. of chocolates = (5 – y)
Parking fees = (20 – z)
Total money spent = (10 + x) (5 – y) + (20 – z)
Was this answer helpful ?
:
Concept: 1Mark
Application: 1 Mark
Price of chocolate = (10 + x)
No. of chocolates = (5 – y)
Parking fees = (20 – z)
Total money spent = (10 + x) (5 – y) + (20 – z)
Was this answer helpful ?
More Questions on This Topic :
Question 1. 5x×(−4yz)×3xz = ___....
Question 2. Simplify:
(xy+yz)2−(xy−yz)2 ....
Question 3. Find the sum of
(11x2−8x+4) and (6x2+7x−10).....
Question 6. The numerical factor of a term is known as....
Question 7. Simplify (3x2+5y2)(4xy−5y).....
Question 10. Using an identity expand :
(2y+5)(2y+5)....
Latest Videos
Latest Test Papers
Submit Solution