Question
`((243)^(n/5) xx 3^(2n + 1))/(9^n xx 3^(n-1))` = ?
Answer: Option C
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`((243)^(n/5) xx 3^(2n + 1))/(9^n xx 3^(n-1))`= `((3^5)^(n/5) xx 3^(2n + 1))/((3^2)^n xx 3^(n-1)`
=`(3(5xxn/5) xx 3^(2n +1))/(3^(2n) xx 3^(n - 1))` = `(3^n xx 3^(2n + 1))/(3^(2n) xx 3^(n - 1))`
=`(3^((n + 2n + 1)))/(3^((2n + n - 1)))` = `(3^(3n + 1))/(3^(2n -1))` = `3^(3n + 1 - 3n + 1)`= `3^2` = 9.
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