12th Grade > Physics
WORK POWER AND ENERGY MCQs
Work And Energy, Sources Of Energy, Electric Potential Energy Potential And Dipoles
Total Questions : 109
| Page 3 of 11 pages
Answer: Option A. -> Differential heating of different landforms causes pressure difference.
:
A
Different parts of Earth receive different intensity of sunlight and also different landforms have different ability to heat-up. The air mass above hotter regions develop low pressure and that above colder regions develop high pressure. Wind blows from high pressure region to low pressure region. Thus sunlight is the ultimate source of energy for winds.
:
A
Different parts of Earth receive different intensity of sunlight and also different landforms have different ability to heat-up. The air mass above hotter regions develop low pressure and that above colder regions develop high pressure. Wind blows from high pressure region to low pressure region. Thus sunlight is the ultimate source of energy for winds.
Answer: Option A. -> Fossil fuels
:
A
The exhaustible natural resources are limited in nature and can be exhausted by different human activities. The inexhaustible natural resources are in unlimited quantity and are not likely to be exhausted by human activities. Fossil fuels are exhaustibleresources, whereas hydro energy, nuclear energy, and wind energy areinexhaustible natural resources.
:
A
The exhaustible natural resources are limited in nature and can be exhausted by different human activities. The inexhaustible natural resources are in unlimited quantity and are not likely to be exhausted by human activities. Fossil fuels are exhaustibleresources, whereas hydro energy, nuclear energy, and wind energy areinexhaustible natural resources.
Answer: Option A. -> The potential energy possessed by the stored water is converted into electricity.
:
A
Waterstored in a dam at a certain height,haspotential energy. This potential energy isconverted to kinetic energy when allowed to flow. The kinetic energy of flowing water is used to turn the turbine, which is used to generate electric current. Hence, the overall conversion is from the potential energy of stored water to electrical energy.
:
A
Waterstored in a dam at a certain height,haspotential energy. This potential energy isconverted to kinetic energy when allowed to flow. The kinetic energy of flowing water is used to turn the turbine, which is used to generate electric current. Hence, the overall conversion is from the potential energy of stored water to electrical energy.
Answer: Option A. -> negative
:
A
When box slides on the ground, friction will act on the boxopposite to the direction of motion. Even on the circular track, if we take any small portion, friction is always opposite to the displacement. Hence work done by the friction =- force × displacement. Therefore, thework done by friction on the toy isnegative work.
:
A
When box slides on the ground, friction will act on the boxopposite to the direction of motion. Even on the circular track, if we take any small portion, friction is always opposite to the displacement. Hence work done by the friction =- force × displacement. Therefore, thework done by friction on the toy isnegative work.
Answer: Option A. -> True
:
A
Mechanical energy is the sum of kinetic energy and potential energy in a system.
The law of conservation of mechanical energy states that the mechanical energy in a systemremains constant as long as the forces applied are conservative(doesn't depend on the path).
:
A
Mechanical energy is the sum of kinetic energy and potential energy in a system.
The law of conservation of mechanical energy states that the mechanical energy in a systemremains constant as long as the forces applied are conservative(doesn't depend on the path).
Answer: Option C. -> 8.3 m
:
C
Given:
Work done, W=1250J
Force, F=150N
Let the distance the rock was raised be s.
Work done is the product of force and displacement of the body along the force.
W=Fs
s=1250150=8.¯3m
Thus, the rock was lifted through a distance of 8.3m.
:
C
Given:
Work done, W=1250J
Force, F=150N
Let the distance the rock was raised be s.
Work done is the product of force and displacement of the body along the force.
W=Fs
s=1250150=8.¯3m
Thus, the rock was lifted through a distance of 8.3m.
Answer: Option B. -> 1.6×10−29
:
B
p=q×(d)=1.6×10−19×10−10=1.6×10−29C−m
:
B
p=q×(d)=1.6×10−19×10−10=1.6×10−29C−m
Answer: Option C. -> 7.68×10−29 Coulomb×m
:
C
Dipole moment p = q (d)
=3.2×10−19×(2.4×10−10)=7.68×10−29C−m
:
C
Dipole moment p = q (d)
=3.2×10−19×(2.4×10−10)=7.68×10−29C−m