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12th Grade > Physics

WORK POWER AND ENERGY MCQs

Work And Energy, Sources Of Energy, Electric Potential Energy Potential And Dipoles

Total Questions : 109 | Page 11 of 11 pages
Question 101. A ball, when kept on a spring attains a certain height after it is compressed and released. For which of the following height attained by the ball, maximum of his energy is required to compress the spring?
  1.    3 m
  2.    5 m
  3.    7 m
  4.    9 m
 Discuss Question
Answer: Option D. -> 9 m
:
D
Maximum energy depends on the work done in compressing the spring which is directly proportional to the height attained by the ball after the spring is released. The gravitational potential energy is expressed as "m x g x h” and it would be the maximum for the height of 9m. So, he has to domaximum work to compress the spring when the ball rises to a height of 9m.
Question 102. A box of mass 2 kg is lifted diagonally from point A to point B as shown in the given figure. Given that the acceleration due to gravity is 10 ms2, what is the gravitational potential energy gained by the box?
A Box Of Mass 2 Kg Is Lifted Diagonally From Point A To Poin...
 
  1.    20 J
  2.    60 J
  3.    80 J
  4.    100 J
 Discuss Question
Answer: Option B. -> 60 J
:
B
Given, mass of the box,m=2kg, vertical height, h=3m and acceleration due to gravity, g=10ms2 .
We know that, gravitational potential energy =mgh=2×10×3=60Joule
Question 103. A man lifts a luggage of 10kg from the ground and puts it on his head 1.7m above the ground. Calculate work done by him on the luggage. Take acceleration due to gravity=10ms2.
  1.    150J
  2.    170J
  3.    180J
  4.    200J
 Discuss Question
Answer: Option B. -> 170J
:
B
Given:
Mass, m=10kg,
Acceleration due to gravity, g=10ms2,
Displacement, s=1.7m.
Force F is calculated as
F=m×g=10×10=100N
Work done by the man onluggage=Force×displacement
W=100×1.7=170J
Hence, the required work done is 170J.
It can be noted that the work is done by the man on the luggage because he lifts it against the gravitational force of the earth.
Question 104. A child is moving on a skateboard at the speed of 2 ms1. After a force acts on him, his speed becomes 3 ms1. Find the work done by the external force on the child, given the mass of the child is 20 kg.
  1.    100 J
  2.    50 J
  3.    20 J
  4.    320 J
 Discuss Question
Answer: Option B. -> 50 J
:
B
Let initial velocity of the child be v1 and final velocity be v2
Given, v1=2ms1, v2=3ms1 and massof the child =20kg.
Since the child is in motion, he will have a kinetic energy ofmv22, which will be increased after an application of force by an external agent on him.
Now, Applying work energy theorem ,
Work done by the external force on the child =mv222mv212
=20×(94)2
=10×5=50J
Question 105. When a lift is going up, the potential energy of the person with respect to earth inside a lift remains the same.
  1.    True
  2.    False
  3.    50 W
  4.    70 W
 Discuss Question
Answer: Option B. -> False
:
B
Potential energy depends on the position of an object with respect to a reference point. In this case, the earth is the reference point. A man on a lift going up, gains height with respect to the earth.
Thus, the potential energy of the person inside the lift increases.
Question 106. Moving train has complete mechanical energy in the form of potential energy.
  1.    True
  2.    False
  3.    Just after touching the ground floor
  4.    Just before touching the ground floor
 Discuss Question
Answer: Option B. -> False
:
B
Moving train has velocity and will have only kinetic energy. A moving train will not gain any height and hence has no potential energy. Therefore, the given statement is wrong.
Question 107. An object is falling from a terrace of height 20m. At what point does it have maximum kinetic energy?
  1.    20m height
  2.    10m height
  3.    Just after touching the ground floor
  4.    Just before touching the ground floor
 Discuss Question
Answer: Option D. -> Just before touching the ground floor
:
D
When the object isat a height of 20m above the ground, it has only potential energy.
Since the velocity of the object increases when it comes down, its kinetic energy will increase. When theobject is just about to touchthe ground, its potential energy will be zeroand kinetic energy will be maximum.
Question 108. Hulk tried to move the wall of a fortress, but unfortunately he was unable to do it. But he applied a very large amount of force to do so, hence work done is positive.
  1.    True
  2.    False
  3.    8.3 m
  4.    7.3 m
 Discuss Question
Answer: Option B. -> False
:
B
Work done by a force is defined as the product of force and displacement of the body along the direction of force. Since Hulk was unable to move the wall, the displacement is zero and irrespective of the large amount of force he applied, work done will be zero.
Question 109. An electric  bulb consumes 7.2 kJ of electrical energy in 2 minutes. What is the power of the electric bulb?
  1.    40 W
  2.    60 W
  3.    50 W
  4.    70 W
 Discuss Question
Answer: Option B. -> 60 W
:
B
Given, energy E=7.2kJ=7.2×103J and time t=2minutes=2×60=120s.
We know, power, P=EnergyorWorkt=7.2×103120=60W.
The power of electric bulb is 60W.

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