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8th Grade > Mathematics

UNDERSTANDING QUADRILATERALS MCQs

Total Questions : 464 | Page 8 of 47 pages
Question 71. Square is a regular quadrilateral.
  1.    True
  2.    False
  3.    140∘
  4.    90∘
 Discuss Question
Answer: Option A. -> True
:
A
A polygon is called a regular polygon if it is equiangular and equilateral. i.e., All the angles are equal and measure of all the sides are equal.
Square is quadrilateral with all the angles equal to 90 and all the sides of equal length.
Square is a regular quadrilateral.
Hence, the given statement is true.

Question 72. ABCD is a parallelogram in which DCB and ABC are in ratio 2:7. Find the sum of ABD and ADB.
ABCD Is A Parallelogram In Which ∠DCB And ∠ABC Are In Ra...
  1.    40∘
  2.    50∘
  3.    70∘
  4.    140∘
 Discuss Question
Answer: Option D. -> 140∘
:
D
ABCD Is A Parallelogram In Which ∠DCB And ∠ABC Are In Ra...
DCB+ABC=180
[Adjacent angles of a parallelogram are supplementary]

2t+7t=180
[DCB and ABC are in ratio 2:7]

t=20
DCB=2t=2×20=40
and ABC=7t=7×20=140
Now, DAB=DCB=40
[Opposite angles of a parallelogram are equal]

DAB+ADB+ABD=180
[Sum of the angles of a triangle]
40+ADB+ABD=180
ADB+ABD=140
Question 73.
If a diagonal of a quadrilateral bisects both the angles, then it is a
a) Kite
b) Parallelogram
c) Rhombus
d) Rectangle
 Discuss Question

:
If a diagonal of a quadrilateral bisects both the angles, then it is a rhombus.
Question 74.
In parallelogram ABCD, the angle bisector of A bisects BC. Will angle bisector of B also bisect AD? Give reason.
 Discuss Question

:
Given, ABCD is a parallelogram, bisector of A, bisects BC at F, i.e. 1=2, CF = FB.
Draw FEBA
ABFE is a parallelogram by construction [FEBA]
1=6 [alternate angle]
In Parallelogram ABCD, The Angle Bisector Of ∠A Bisects BC...
But 1=2 [given]
2=6
AB = FB [opposite sides to equal angles are equal] ..... (i)
ABFEisarhombus.
Now, in ΔABO and ΔBOF, AB = BF [from Eq. (i)]
BO = BO [common]
AO = FO [diagonals of rhombus bisect each other]
ΔABOΔBOF [by SSS]
3=4 [by CPCT]
Now, BF=12BC [given]
BF=12AD [BC = AD]
AE=12AD [BF = AE]
E is the mid-point of AD.
Question 75.
A parallelogram can be constructed uniquely, if both diagonals and the angle between them is given.
 Discuss Question

:
True
We can draw a unique parallelogram, if both diagonals and the angle between them is given.
A Parallelogram Can Be Constructed Uniquely, If Both Diagona...
Question 76.
Which of the following is an equiangular and equilateral polygon?
a) Square
b) Rectangle
c) Rhombus
d) Right angled Triangle
 Discuss Question

:
In a square, all the sides and all the angles are equal.
Hence, square is an equiangular and equilateral polygon.
Question 77.
All rectangles are parallelograms.
 Discuss Question

:
True
Rectangles are special parallelograms and satisfy all properties of parallelograms. Therefore, we can say that all rectangles are parallelograms but vice-versa is not true.
Question 78.
Two angles of a quadrilateral are each of measure 75 and the other two angles are equal. What is the measure of these two angles? Name the possible figures so formed.
 Discuss Question

:
Let ABCD be a quadrilateral,
where A=C=75 and B=D=x [say]
Two Angles Of A Quadrilateral Are Each Of Measure 75∘ And ...
Then, by the angle sum property of a quadrilateral, we have
A+B+C+D=36075+x+75+x=3602x=3601502x=210x=105
Thus, other two angles are of 105 each.
Since, opposite angles are equal, therefore the quadrilateral is a parallelogram.
Question 79.
What is the maximum number of obtuse angles that a quadrilateral can have?
a) 1
b) 2
c) 3
d) 4
 Discuss Question

:
We know that the sum of all the angles of a quadrilateral is 360.
Also, an obtuse angle is more than 90 and less than 180.
Thus, all the angles of a quadrilateral cannot be obtuse.
Hence, at the most 3 angles can be obtuse.
Question 80.
In the following figure, FDBCAE and ACED. Find the value of x.
In The Following Figure, FD∥BC∥AE And AC∥ED. Find The ...
 Discuss Question

:
In The Following Figure, FD∥BC∥AE And AC∥ED. Find The ...
In ΔABC,
ABC+BCA+CAB=180 [Angle sum property of triangle]
64+BCA+52=180
BCA=1806452=64
FAE=BCA [ Alternate angles; AEBC, AC is the transversal]
FAE=64
Now, FAE+x=180 [Adjacent angles in a parallelogram are supplementary]
x=18064x=116

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