8th Grade > Mathematics
UNDERSTANDING QUADRILATERALS MCQs
Total Questions : 464
| Page 47 of 47 pages
Answer: Option A. ->
:
Fourth angle =360∘−(60∘+110∘+85∘)=360∘−255∘=105∘
Steps of Construction
Step I Draw NE = 7 cm.
Step II Make ∠NEX=110∘.
Step III With E as centre and radius 6 cm, draw an arc, cutting EX at W.
Step IV Make ∠EWY=105∘.
Step V Make ∠ENZ=60∘, so that NZ and WY intersect each other at point S.
Thus, NEWS is the required quadrilateral.
:
Fourth angle =360∘−(60∘+110∘+85∘)=360∘−255∘=105∘
Steps of Construction
Step I Draw NE = 7 cm.
Step II Make ∠NEX=110∘.
Step III With E as centre and radius 6 cm, draw an arc, cutting EX at W.
Step IV Make ∠EWY=105∘.
Step V Make ∠ENZ=60∘, so that NZ and WY intersect each other at point S.
Thus, NEWS is the required quadrilateral.
Answer: Option A. ->
:
Steps of Construction
Step I Draw AB = 4 cm.
Step II With A as centre and radius 2.8 cm, draw an arc.
Step III With B as centre and radius 3.5 cm, draw another arc, cutting the previous arc at O.
Step IV Join OA and OB.
Step V Produce AO to C such that OC = AO and produce BO to D such that OD = BD.
Step VI Join AD, BC and CD.
Thus, ABCD is the required parallelogram.
and other side = 5 cm.
:
Steps of Construction
Step I Draw AB = 4 cm.
Step II With A as centre and radius 2.8 cm, draw an arc.
Step III With B as centre and radius 3.5 cm, draw another arc, cutting the previous arc at O.
Step IV Join OA and OB.
Step V Produce AO to C such that OC = AO and produce BO to D such that OD = BD.
Step VI Join AD, BC and CD.
Thus, ABCD is the required parallelogram.
and other side = 5 cm.
Answer: Option A. ->
:
Steps of Construction
Step I Draw a line segment DC = 9.6 cm.
Step II With D as center, draw an angle measure 60∘. Now, cut-off it with an arc 3.2 cm called point A.
Step III Now, draw a parallel AB to CD.
Step IV Taking C as center, cut an arc B measure 3.2 cm on previous parallel line.
Step V Draw a line segment BE = 3.2 cm from arc B.
Step VI Join B to E and C.
Thus, we have required trapezium ABCD in which ∠A=120∘ and ∠B=∠EBC+∠ABE=60∘+60∘=120∘. (Since, BEC is an equilateral triangle and ABED is a parallelogam)
:
Steps of Construction
Step I Draw a line segment DC = 9.6 cm.
Step II With D as center, draw an angle measure 60∘. Now, cut-off it with an arc 3.2 cm called point A.
Step III Now, draw a parallel AB to CD.
Step IV Taking C as center, cut an arc B measure 3.2 cm on previous parallel line.
Step V Draw a line segment BE = 3.2 cm from arc B.
Step VI Join B to E and C.
Thus, we have required trapezium ABCD in which ∠A=120∘ and ∠B=∠EBC+∠ABE=60∘+60∘=120∘. (Since, BEC is an equilateral triangle and ABED is a parallelogam)
Answer: Option A. ->
:
∠I+∠S=180∘
60∘+∠S=180∘ [cointerior angles]
∠S=120∘
Steps of Construction
Step I Draw an arc RI = 7 cm.
Step II Make ∠RIX=60∘.
Step III With I as centre and radius 5 cm, draw an arc, cutting IX at S.
Step IV Make ∠ISY=120∘.
Step V With R as centre and radius 6.5 cm, draw an arc cutting SY at K.
Step VI Join KR.
Thus, RISK is the required trapezium.
:
∠I+∠S=180∘
60∘+∠S=180∘ [cointerior angles]
∠S=120∘
Steps of Construction
Step I Draw an arc RI = 7 cm.
Step II Make ∠RIX=60∘.
Step III With I as centre and radius 5 cm, draw an arc, cutting IX at S.
Step IV Make ∠ISY=120∘.
Step V With R as centre and radius 6.5 cm, draw an arc cutting SY at K.
Step VI Join KR.
Thus, RISK is the required trapezium.
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