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Quantitative Aptitude > Discount

TRUE DISCOUNT MCQs

Total Questions : 223 | Page 7 of 23 pages
Question 61. The equivalent single discount for two successive discounts of 15% and 10% is
  1.    20.5%
  2.    23.5%
  3.    25%
  4.    20%
 Discuss Question
Answer: Option B. -> 23.5%
Answer: (b)Trick :Equivalent discount= $(15 + 10 - {15 × 10}/100)%$ = 23.5%
Question 62. A company offers three types of successive discounts : (i) 25% and 15%, (ii) 30% and 10%, (iii) 35% and 5%. Which offer is the best for a customer?
  1.    Any one; all are equally good
  2.    Third offer
  3.    First offer
  4.    Second offer
 Discuss Question
Answer: Option B. -> Third offer
Answer: (b)Using Rule 5,(i) : Equivalent discount= $(25 + 15 - {25 × 15}/100)$%= (40 - 3.75) % = 36.25%(ii) : Equivalent discount= $(30 + 10 - {30 × 10}/100)$%= (40 - 3) % = 37%(iii) : Equivalent discount= $(35 + 5 - {35 × 5}/100)$%= (40 - 1.75) % = 38.25%Clearly, third offer is best for a customer
Question 63. Applied to a bill for Rs.1,00,000 the difference between a discount of 40% and two successive discounts of 36% and 4% is :
  1.    Rs.4,000
  2.    Rs.2,500
  3.    Nil
  4.    Rs.1,440
 Discuss Question
Answer: Option D. -> Rs.1,440
Answer: (d)Using Rule 5,(Special Case) : When two successive disounts are given, then overall discount is =$(D_1 + D_2 - {D_1D_2}/100)%$
Question 64. Two successive discounts of 20% and 20% is equivalent to a single discount of
  1.    34%
  2.    36%
  3.    42%
  4.    40%
 Discuss Question
Answer: Option B. -> 36%
Answer: (b)Using Rule 5,Equivalent single discount= $(20 + 20 - {20 × 20}/100)$% = 36%
Question 65. Successive discounts of 10% and 30% are equivalent to a single discount of :
  1.    37%
  2.    38%
  3.    40%
  4.    35%
 Discuss Question
Answer: Option A. -> 37%
Answer: (a)Using Rule 5,Equivalent discount= 30 + 10 - ${30 × 10}/100$ = 37%
Question 66. The difference between a single discount of 30% on Rs.550 and two successive discounts of 20% and 10% on the same amount is
  1.    Rs.44
  2.    Rs.22
  3.    Nil
  4.    Rs.11
 Discuss Question
Answer: Option D. -> Rs.11
Answer: (d)Using Rule 5,(Special Case) : When two successive disounts are given, then overall discount is =$(D_1 + D_2 - {D_1D_2}/100)%$
Question 67. The marked price of an article is Rs.500. It is sold at successive discounts of 20% and 10%. The selling price of the article (in rupees) is :
  1.    400
  2.    360
  3.    350
  4.    375
 Discuss Question
Answer: Option B. -> 360
Answer: (b)Equivalent discount of successive discounts of 20% and 10%= $(20 + 10 - {20 × 10}/100)$% = 28%Selling Price = (100 - 28) % of Rs.500 = 72 % of 500= Rs.${500 × 72}/100$ = Rs.360 Using Rule 3,When successive Discounts $D_1, D_2, D_3$, so on, are given thenSP = MP$({100 - D_1}/100)({100 - D_2}/100)({100 - D_3}/100)$
Question 68. An article is listed at Rs.920. A customer pays Rs.742.90 for it after getting two successive discounts. If the rate of first discount is 15%, the rate of 2nd discount is
  1.    12%
  2.    8%
  3.    3%
  4.    5%
 Discuss Question
Answer: Option D. -> 5%
Answer: (d)Total discount= Rs.(920 - 742.90) = Rs.177.10First discount = 15%Discount = 15% of 920= ${920 × 15}/100$ = Rs.138Price after this discount= 920 - 138 = Rs.782Remaining discount= 177.10 - 138 = Rs.39.10Let the second discount be x %.${782 × x}/100 = 39.10$$x = {39.10 × 100}/782$ = 5%Using Rule 3,Here, M.P. = Rs.920, S.P. = Rs.742.90, $D_1 = 15%, D_2$ = ?S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$742.90 = 920 $({100 - 15}/100)({100 - D_2}/100)$$7429000/{920 × 85} = 100 - D_2$95 = 100 - $D_2 ⇒ D_2$ = 5%
Question 69. If on a marked price, the difference of selling prices with a discount of 30% and two successive discounts of 20% and 10% is Rs.72, then the marked price (in rupees) is
  1.    2,400
  2.    2,500
  3.    3,600
  4.    3,000
 Discuss Question
Answer: Option C. -> 3,600
Answer: (c)Using Rule 5,Let the marked price be Rs.x.In case I, SP = Rs.${70x}/100$Single discount equivalent to successive discounts of 20% and 10%.= $(20 + 10 - {20 × 10}/100)$% = 28%S.P. in this case = ${72x}/100$${72x}/100 - {70x}/100$ = 72${2x}/100 = 72$$x = {72 × 100}/2$ = Rs.3600
Question 70. The marked price of a watch was Rs.720/-. A man bought the same for Rs.550.80, after getting two successive discounts, the first at 10%. What was the second discount rate?
  1.    18%
  2.    15%
  3.    12%
  4.    14%
 Discuss Question
Answer: Option B. -> 15%
Answer: (b)Marked price = Rs.720Actual price = Rs.550.80First discount = 10%Let the second discount be x%Then, we can write720 (1 - 0.10) (1–0.01x) = 550.80720 × 0.9 (1– 0.01x) = 550.8648 (1 - 0.01x) = 550.81 - 0.01 x= ${550.8}/648$0.01 x = $1 - {550.8}/648$$x = {1 - 0.85}/{0.01}$x = 0.15 × 100 ⇒ x= 15Second discount = 15%

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