Quantitative Aptitude > Discount
TRUE DISCOUNT MCQs
Total Questions : 223
| Page 7 of 23 pages
Answer: Option B. -> 23.5%
Answer: (b)Trick :Equivalent discount= $(15 + 10 - {15 × 10}/100)%$ = 23.5%
Answer: (b)Trick :Equivalent discount= $(15 + 10 - {15 × 10}/100)%$ = 23.5%
Answer: Option B. -> Third offer
Answer: (b)Using Rule 5,(i) : Equivalent discount= $(25 + 15 - {25 × 15}/100)$%= (40 - 3.75) % = 36.25%(ii) : Equivalent discount= $(30 + 10 - {30 × 10}/100)$%= (40 - 3) % = 37%(iii) : Equivalent discount= $(35 + 5 - {35 × 5}/100)$%= (40 - 1.75) % = 38.25%Clearly, third offer is best for a customer
Answer: (b)Using Rule 5,(i) : Equivalent discount= $(25 + 15 - {25 × 15}/100)$%= (40 - 3.75) % = 36.25%(ii) : Equivalent discount= $(30 + 10 - {30 × 10}/100)$%= (40 - 3) % = 37%(iii) : Equivalent discount= $(35 + 5 - {35 × 5}/100)$%= (40 - 1.75) % = 38.25%Clearly, third offer is best for a customer
Answer: Option D. -> Rs.1,440
Answer: (d)Using Rule 5,(Special Case) : When two successive disounts are given, then overall discount is =$(D_1 + D_2 - {D_1D_2}/100)%$
Answer: (d)Using Rule 5,(Special Case) : When two successive disounts are given, then overall discount is =$(D_1 + D_2 - {D_1D_2}/100)%$
Answer: Option B. -> 36%
Answer: (b)Using Rule 5,Equivalent single discount= $(20 + 20 - {20 × 20}/100)$% = 36%
Answer: (b)Using Rule 5,Equivalent single discount= $(20 + 20 - {20 × 20}/100)$% = 36%
Answer: Option A. -> 37%
Answer: (a)Using Rule 5,Equivalent discount= 30 + 10 - ${30 × 10}/100$ = 37%
Answer: (a)Using Rule 5,Equivalent discount= 30 + 10 - ${30 × 10}/100$ = 37%
Answer: Option D. -> Rs.11
Answer: (d)Using Rule 5,(Special Case) : When two successive disounts are given, then overall discount is =$(D_1 + D_2 - {D_1D_2}/100)%$
Answer: (d)Using Rule 5,(Special Case) : When two successive disounts are given, then overall discount is =$(D_1 + D_2 - {D_1D_2}/100)%$
Answer: Option B. -> 360
Answer: (b)Equivalent discount of successive discounts of 20% and 10%= $(20 + 10 - {20 × 10}/100)$% = 28%Selling Price = (100 - 28) % of Rs.500 = 72 % of 500= Rs.${500 × 72}/100$ = Rs.360 Using Rule 3,When successive Discounts $D_1, D_2, D_3$, so on, are given thenSP = MP$({100 - D_1}/100)({100 - D_2}/100)({100 - D_3}/100)$
Answer: (b)Equivalent discount of successive discounts of 20% and 10%= $(20 + 10 - {20 × 10}/100)$% = 28%Selling Price = (100 - 28) % of Rs.500 = 72 % of 500= Rs.${500 × 72}/100$ = Rs.360 Using Rule 3,When successive Discounts $D_1, D_2, D_3$, so on, are given thenSP = MP$({100 - D_1}/100)({100 - D_2}/100)({100 - D_3}/100)$
Answer: Option D. -> 5%
Answer: (d)Total discount= Rs.(920 - 742.90) = Rs.177.10First discount = 15%Discount = 15% of 920= ${920 × 15}/100$ = Rs.138Price after this discount= 920 - 138 = Rs.782Remaining discount= 177.10 - 138 = Rs.39.10Let the second discount be x %.${782 × x}/100 = 39.10$$x = {39.10 × 100}/782$ = 5%Using Rule 3,Here, M.P. = Rs.920, S.P. = Rs.742.90, $D_1 = 15%, D_2$ = ?S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$742.90 = 920 $({100 - 15}/100)({100 - D_2}/100)$$7429000/{920 × 85} = 100 - D_2$95 = 100 - $D_2 ⇒ D_2$ = 5%
Answer: (d)Total discount= Rs.(920 - 742.90) = Rs.177.10First discount = 15%Discount = 15% of 920= ${920 × 15}/100$ = Rs.138Price after this discount= 920 - 138 = Rs.782Remaining discount= 177.10 - 138 = Rs.39.10Let the second discount be x %.${782 × x}/100 = 39.10$$x = {39.10 × 100}/782$ = 5%Using Rule 3,Here, M.P. = Rs.920, S.P. = Rs.742.90, $D_1 = 15%, D_2$ = ?S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$742.90 = 920 $({100 - 15}/100)({100 - D_2}/100)$$7429000/{920 × 85} = 100 - D_2$95 = 100 - $D_2 ⇒ D_2$ = 5%
Answer: Option C. -> 3,600
Answer: (c)Using Rule 5,Let the marked price be Rs.x.In case I, SP = Rs.${70x}/100$Single discount equivalent to successive discounts of 20% and 10%.= $(20 + 10 - {20 × 10}/100)$% = 28%S.P. in this case = ${72x}/100$${72x}/100 - {70x}/100$ = 72${2x}/100 = 72$$x = {72 × 100}/2$ = Rs.3600
Answer: (c)Using Rule 5,Let the marked price be Rs.x.In case I, SP = Rs.${70x}/100$Single discount equivalent to successive discounts of 20% and 10%.= $(20 + 10 - {20 × 10}/100)$% = 28%S.P. in this case = ${72x}/100$${72x}/100 - {70x}/100$ = 72${2x}/100 = 72$$x = {72 × 100}/2$ = Rs.3600
Answer: Option B. -> 15%
Answer: (b)Marked price = Rs.720Actual price = Rs.550.80First discount = 10%Let the second discount be x%Then, we can write720 (1 - 0.10) (1–0.01x) = 550.80720 × 0.9 (1– 0.01x) = 550.8648 (1 - 0.01x) = 550.81 - 0.01 x= ${550.8}/648$0.01 x = $1 - {550.8}/648$$x = {1 - 0.85}/{0.01}$x = 0.15 × 100 ⇒ x= 15Second discount = 15%
Answer: (b)Marked price = Rs.720Actual price = Rs.550.80First discount = 10%Let the second discount be x%Then, we can write720 (1 - 0.10) (1–0.01x) = 550.80720 × 0.9 (1– 0.01x) = 550.8648 (1 - 0.01x) = 550.81 - 0.01 x= ${550.8}/648$0.01 x = $1 - {550.8}/648$$x = {1 - 0.85}/{0.01}$x = 0.15 × 100 ⇒ x= 15Second discount = 15%