Question
A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?
Answer: Option D
- Let the length of the train be x metres and its speed by y m/sec.
Then, x = 8 x = 8y y Now, x + 264 = y 20
8y + 264 = 20y
y = 22.
Speed = 22 m/sec = 22 x 18 km/hr = 79.2 km/hr. 5
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- Let the length of the train be x metres and its speed by y m/sec.
Then, x = 8 x = 8y y Now, x + 264 = y 20
8y + 264 = 20y
y = 22.
Speed = 22 m/sec = 22 x 18 km/hr = 79.2 km/hr. 5
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