11th Grade > Mathematics
STATISTICS MCQs
Total Questions : 30
| Page 1 of 3 pages
Answer: Option B. ->
¯x+n+1
:
B
¯x=∑ni=1xin⇒∑ni=1xi=n¯x∴ ∑ni(xi+2i)n=∑ni=1xi+2(1+2+...+n)n=n¯x+2n(n+1)2n=¯x+(n+1)
:
B
¯x=∑ni=1xin⇒∑ni=1xi=n¯x∴ ∑ni(xi+2i)n=∑ni=1xi+2(1+2+...+n)n=n¯x+2n(n+1)2n=¯x+(n+1)
Answer: Option A. ->
16
:
A
:
A
Range = Highest observation - Lowest observation
= 19 − 3
= 16
Answer: Option A. ->
less than 3
:
A
¯x=−1+0+43=1.∴ Mean Deviation = 13[|−1−1|+|0−1|+|4−1|]=2
:
A
¯x=−1+0+43=1.∴ Mean Deviation = 13[|−1−1|+|0−1|+|4−1|]=2
Answer: Option C. ->
6
:
C
6=3+4+x+7+105
⇒30=24+x
⇒x=6
:
C
6=3+4+x+7+105
⇒30=24+x
⇒x=6
Answer: Option D. ->
remains the same as that of the original set
:
D
We know that median is found when we arrange the observations in ascending or descending order. And if the number of observations are odd then it is the n+12th term.
Since on arranging 9 observations 5th will be the median.
On changing 4 of any side won't affect the median and it'll remain same.
:
D
We know that median is found when we arrange the observations in ascending or descending order. And if the number of observations are odd then it is the n+12th term.
Since on arranging 9 observations 5th will be the median.
On changing 4 of any side won't affect the median and it'll remain same.
Answer: Option C. ->
26
:
C
:
C
Sum of total number =18×5=90
After one number excluded
Sum of total number =16×4=64
Then, excluded number is 90−64=26
Answer: Option C. ->
√3
:
C
:
C
Given that median = 4 and mode = 6. We know that
Mean - mode = 3 (Mean - Median)
Mean - 6 = 3 (Mean - 4)
¯x−6=3¯x−12
¯x=3
σ2=∑x2in−(∑xin)2=484−(3)2=3 ∴σ=√3
Answer: Option C. ->
57 kg
:
C
Total weight of 7 students is =55×7=385kg
Sum of weight of 6 students
=52+58+55+53+56+54=328kg
∴ Weight of seventh student =385–328=57kg.
:
C
Total weight of 7 students is =55×7=385kg
Sum of weight of 6 students
=52+58+55+53+56+54=328kg
∴ Weight of seventh student =385–328=57kg.
Answer: Option C. ->
¯¯¯x+10αα
:
C
Let x1,x2……,xn be n observations.
Then ¯¯¯x=1n∑xi
let yi=xiα+10
¯¯¯y=1nn∑iyi
And, ¯¯¯y=1n[(n∑ixiα+10.n]
⇒¯¯¯y=1α¯¯¯x+10
=¯¯¯x+10αα.
:
C
Let x1,x2……,xn be n observations.
Then ¯¯¯x=1n∑xi
let yi=xiα+10
¯¯¯y=1nn∑iyi
And, ¯¯¯y=1n[(n∑ixiα+10.n]
⇒¯¯¯y=1α¯¯¯x+10
=¯¯¯x+10αα.
Answer: Option C. ->
Team A is more consistent than team B.
:
C
We know that, lesser is the coefficient of variation, the data is more consistent.
Since C.V. of the team A is 2.5, which is less than the C.V. of team B, we can conclude that team A is more Consistent.
:
C
We know that, lesser is the coefficient of variation, the data is more consistent.
Since C.V. of the team A is 2.5, which is less than the C.V. of team B, we can conclude that team A is more Consistent.