9th Grade > Mathematics
STATISTICS MCQs
Total Questions : 53
| Page 3 of 6 pages
Answer: Option B. -> 143
:
B
We know that,
The mode of a set of observations is the observation that occurs most often.
We arrange the given data in the following way:
124, 132, 135, 143, 143, 143, 149, 150, 152 ,158 .
We see that in the above observation 143 is the height of themaximum number of students.
Hence, the mode of the given data is 143.
:
B
We know that,
The mode of a set of observations is the observation that occurs most often.
We arrange the given data in the following way:
124, 132, 135, 143, 143, 143, 149, 150, 152 ,158 .
We see that in the above observation 143 is the height of themaximum number of students.
Hence, the mode of the given data is 143.
Answer: Option A. -> False
:
A
We don't need to draw a histogram in order to draw a frequency polygon. We can obtain the class mark corresponding to each class interval, which corresponds to the midpoint of the class interval along the x-axis and the corresponding frequency along the y-axis.The lines joining these points will constitute the frequency polygon.
:
A
We don't need to draw a histogram in order to draw a frequency polygon. We can obtain the class mark corresponding to each class interval, which corresponds to the midpoint of the class interval along the x-axis and the corresponding frequency along the y-axis.The lines joining these points will constitute the frequency polygon.
Answer: Option C. ->
15.55
:
C
:
C
We know that,
Average or mean value of a given number of observations is the sum of all the observations divided by the total number of observations.
⇒Mean=∑xifi∑fi
Now,
∑xifi=20+65+112+114=311
∑fi=20
So,
Mean=∑xifi∑fi=31120=15.55
Answer: Option B. ->
14
:
B
:
B
Average or mean value of a given number of observations is the sum of all the observations divided by the total number of observations.
xi10p182125fi1015799xifi10015p126189225
Mean =∑xifi∑fi
∑xifi = 100 + 15p + 126 + 189 + 225
= 640 + 15p
∑fi = 50
given that mean = 17
⇒ 640 + 15p = 50 x 17
⇒ 15p = 210
⇒ p = 14
Answer: Option B. ->
143
:
B
We know that,
The mode of a set of observations is the observation that occurs most often.
We arrange the given data in the following way:
124, 132, 135, 143, 143, 143, 149, 150, 152 , 158 .
We see that in the above observation 143 is the height of the maximum number of students.
Hence, the mode of the given data is 143.
:
B
We know that,
The mode of a set of observations is the observation that occurs most often.
We arrange the given data in the following way:
124, 132, 135, 143, 143, 143, 149, 150, 152 , 158 .
We see that in the above observation 143 is the height of the maximum number of students.
Hence, the mode of the given data is 143.
Answer: Option C. ->
Class interval
:
C
:
C
Class interval or class size is basically the size of the interval which depicts the entities contained in it.
Answer: Option A. ->
False
:
A
:
A
We don't need to draw a histogram in order to draw a frequency polygon. We can obtain the class mark corresponding to each class interval, which corresponds to the midpoint of the class interval along the x-axis and the corresponding frequency along the y-axis. The lines joining these points will constitute the frequency polygon.
Answer: Option A. ->
55-65
:
A
The peak of the frequency polygon corresponds to 60 marks. 60 is the class mark of class 55-65. Hence the class 55-65 has the maximum number of students.
:
A
The peak of the frequency polygon corresponds to 60 marks. 60 is the class mark of class 55-65. Hence the class 55-65 has the maximum number of students.
Answer: Option A. ->
55-65
:
:
The frequencies of different observations are given in the table.
It can be seen that shirts of size 41 have the maximum frequency of 90.
So, the mode is 41 and size 41 is the size most in demand.
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