9th Grade > Mathematics
STATISTICS MCQs
Total Questions : 53
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Answer: Option B. -> False
:
B
A bar graph is used to represent data that have different categories while histogram is used to represent classes that are continuous by bars which are side-by-side. Thus they both are different.
:
B
A bar graph is used to represent data that have different categories while histogram is used to represent classes that are continuous by bars which are side-by-side. Thus they both are different.
Answer: Option C. -> Class interval
:
C
Class interval or class size is basically the size of the interval which depicts the entities contained in it.
:
C
Class interval or class size is basically the size of the interval which depicts the entities contained in it.
Answer: Option B. -> 14
:
B
Average or mean value of a given number of observations is the sum of all the observations divided by the total number of observations.
xi10p182125fi1015799xifi10015p126189225
Mean =∑xifi∑fi
∑xifi = 100 + 15p + 126 + 189 + 225
= 640 + 15p
∑fi = 50
given that mean = 17
⇒ 640 + 15p = 50 x 17
⇒ 15p = 210
⇒ p = 14
:
B
Average or mean value of a given number of observations is the sum of all the observations divided by the total number of observations.
xi10p182125fi1015799xifi10015p126189225
Mean =∑xifi∑fi
∑xifi = 100 + 15p + 126 + 189 + 225
= 640 + 15p
∑fi = 50
given that mean = 17
⇒ 640 + 15p = 50 x 17
⇒ 15p = 210
⇒ p = 14
Answer: Option A. -> Bar Graph
:
A
The given description is the one about a bar graph. In a bar graph,rectangular bars of uniform width are drawn with equal spacing between them on one of the coordinate axes, usually the x-axis, to represent the type of variables. The frequency of variable is projected on the other axis i.e. the y-axis.
:
A
The given description is the one about a bar graph. In a bar graph,rectangular bars of uniform width are drawn with equal spacing between them on one of the coordinate axes, usually the x-axis, to represent the type of variables. The frequency of variable is projected on the other axis i.e. the y-axis.
Answer: Option A. -> True
:
A
Bar graphs are usually used to display "categorical data" i.e.data that fits into categories. Histograms, on the other hand, are usually used to present "continuous data",
:
A
Bar graphs are usually used to display "categorical data" i.e.data that fits into categories. Histograms, on the other hand, are usually used to present "continuous data",
Answer: Option B. -> 15
:
B
Median is the middle observation of the given data, when arranged in either ascending or descending order.
Arrangingthe observations in ascending order, we get
6, 9, 13 , 14, 15, 15, 18, 21, 22, 42
Since, there are even number of observations.
Now median,
= Average of (n2)thobservation and (n2+1)thobservation
=5thterm+6thterm2
= 15+152
= 15
Thus, median of the given data is 15.
:
B
Median is the middle observation of the given data, when arranged in either ascending or descending order.
Arrangingthe observations in ascending order, we get
6, 9, 13 , 14, 15, 15, 18, 21, 22, 42
Since, there are even number of observations.
Now median,
= Average of (n2)thobservation and (n2+1)thobservation
=5thterm+6thterm2
= 15+152
= 15
Thus, median of the given data is 15.
Answer: Option D. -> 18
:
D
3, 4, and 5 are thenumbers greater than 2 but less than or equal to 5
So, frequency of getting 3,4, and5 is
= 6 + 4 + 8
= 18
Hence,the frequency of getting a number greater than 2 and less than equal to 5 is 18.
:
D
3, 4, and 5 are thenumbers greater than 2 but less than or equal to 5
So, frequency of getting 3,4, and5 is
= 6 + 4 + 8
= 18
Hence,the frequency of getting a number greater than 2 and less than equal to 5 is 18.
Answer: Option D. -> 15
:
D
Let, the observations be a, b, c, d, e.
We know that,
Mean = SumofallobservationsNumberofobservations
Now,
mean of 5 observations = 12
⇒a+b+c+d+e5=12
⇒a+b+c+d+e=60.....(i)
It is also given that the mean of the first three observations is 10
⇒a+b+c3=10
⇒a+b+c=30...........(ii)
From (i) and (ii) we get
d + e = 30
Hence, the mean of the other two observations i.e. 'd' and 'e' is
=d+e2=15
:
D
Let, the observations be a, b, c, d, e.
We know that,
Mean = SumofallobservationsNumberofobservations
Now,
mean of 5 observations = 12
⇒a+b+c+d+e5=12
⇒a+b+c+d+e=60.....(i)
It is also given that the mean of the first three observations is 10
⇒a+b+c3=10
⇒a+b+c=30...........(ii)
From (i) and (ii) we get
d + e = 30
Hence, the mean of the other two observations i.e. 'd' and 'e' is
=d+e2=15
:
To obtain the median of a given set of data,we have to arrange the data in ascending or descending order. After arranging in ascending order, we get
45, 76, 87, 89, 101, 121, 134, 202, 212, 323.
Here, we have even number of observations i.e. n = 10. So, we will obtain themedian bytaking the mean of the value of 5th and6thobservation i.e.101+1212=111
Answer: Option B. -> False
:
B
By convention, bars of all categories in a bar graph are drawn with equal width. Hence the above statement is false.
:
B
By convention, bars of all categories in a bar graph are drawn with equal width. Hence the above statement is false.