Quantitative Aptitude > Interest
SIMPLE & COMPOUND INTEREST MCQs
Compound Interest, Simple Interest, Interest (combined)
Total Questions : 1171
| Page 115 of 118 pages
Answer: Option A. -> Rs. 992
PRINCIPAL = 800 SI = 120 TIME = 3 YEAR
RATE = (100*120/800*3) = 5%
NEW RATE = 8 % PRINCIPAL = 800 TIME 3 YEAR
SI = (800*8*3/100) = 192
NEW AMOUNT = 800 + 192= 992
PRINCIPAL = 800 SI = 120 TIME = 3 YEAR
RATE = (100*120/800*3) = 5%
NEW RATE = 8 % PRINCIPAL = 800 TIME 3 YEAR
SI = (800*8*3/100) = 192
NEW AMOUNT = 800 + 192= 992
Answer: Option A. -> 6%
1. TO FIND THE INTEREST, SUBTRACT THE PRINCIPAL FROM THE BALANCE.
$618 – $600 = $18
2.USE THE SIMPLE INTEREST FORMULA AND SOLVE FOR R.
I = PRT
18= 600 X R X (1/2)
R= 0.06 =6%
1. TO FIND THE INTEREST, SUBTRACT THE PRINCIPAL FROM THE BALANCE.
$618 – $600 = $18
2.USE THE SIMPLE INTEREST FORMULA AND SOLVE FOR R.
I = PRT
18= 600 X R X (1/2)
R= 0.06 =6%
Answer: Option A. -> Rs.750
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
Answer: Option D. -> Rs. 698
SIMPLE INTEREST (SI) FOR 1 YEAR = 854-815 = 39
SIMPLE INTEREST (SI) FOR 3 YEARS = 39 × 3 = 117
PRINCIPAL = 815 – 117 = RS.698
SIMPLE INTEREST (SI) FOR 1 YEAR = 854-815 = 39
SIMPLE INTEREST (SI) FOR 3 YEARS = 39 × 3 = 117
PRINCIPAL = 815 – 117 = RS.698
Answer: Option B. -> 14/3%
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
Answer: Option C. -> 12%
S.I. FOR 3 YEARS = RS. (12005 – 9800) = RS. 2205.
S.I. FOR 5 YEARS = RS.[ (2205/3) X 5 ] = RS.3675
PRINCIPLE = RS.(9800-3675) = RS.6125
RATE=12%
S.I. FOR 3 YEARS = RS. (12005 – 9800) = RS. 2205.
S.I. FOR 5 YEARS = RS.[ (2205/3) X 5 ] = RS.3675
PRINCIPLE = RS.(9800-3675) = RS.6125
RATE=12%
Answer: Option B. -> 56 years
SIMPLE INTEREST IS GIVEN BY THE FORMULA SI = (PNR/100), WHERE P IS THE PRINCIPAL, N IS THE NUMBEROF YEARS FOR WHICH IT IS INVESTED, R IS THE RATE OF INTEREST PER ANNUM
IN THIS CASE, RS. 1250 HAS BECOME RS.10,000.
THEREFORE, THE INTEREST EARNED = 10,000 – 1250 = 8750.
8750 = [(1250 X N X 12.5)/100]
=> N = 700 / 12.5 = 56 YEARS.
SIMPLE INTEREST IS GIVEN BY THE FORMULA SI = (PNR/100), WHERE P IS THE PRINCIPAL, N IS THE NUMBEROF YEARS FOR WHICH IT IS INVESTED, R IS THE RATE OF INTEREST PER ANNUM
IN THIS CASE, RS. 1250 HAS BECOME RS.10,000.
THEREFORE, THE INTEREST EARNED = 10,000 – 1250 = 8750.
8750 = [(1250 X N X 12.5)/100]
=> N = 700 / 12.5 = 56 YEARS.
Answer: Option D. -> Rs.6000
LET SUM = P AND ORIGINAL RATE = R. THEN
[(P * (R+2) * 3)/100] – [ (P * R * 3)/100] = 360
3P*(R+2) – 3PR = 36000
3PR + 6P – 3PR = 36000
6P = 36000
P = 6000
LET SUM = P AND ORIGINAL RATE = R. THEN
[(P * (R+2) * 3)/100] – [ (P * R * 3)/100] = 360
3P*(R+2) – 3PR = 36000
3PR + 6P – 3PR = 36000
6P = 36000
P = 6000
Answer: Option B. -> Rs.2700
LET THE MAN INVESTS RS.X AT 6% AND RS.Y AT 7%
SIMPLE INTEREST ON RS.X AT 6% FOR 2 YEARS + SIMPLE INTEREST ON RS.Y AT 7% FOR 2 YEARS = RS.354
X×6×2/100+Y×7×2/
LET THE MAN INVESTS RS.X AT 6% AND RS.Y AT 7%
SIMPLE INTEREST ON RS.X AT 6% FOR 2 YEARS + SIMPLE INTEREST ON RS.Y AT 7% FOR 2 YEARS = RS.354
X×6×2/100+Y×7×2/
Answer: Option D. -> 13.75%
SIMPLE INTEREST, SI = (3875 – 2500) = RS.1375
PRINCIPAL, P = RS. 2500
TIME, T = 4 YEARS
R = ?
R=100×SI/PT=100×13752/500×4
=100×1375/10000=13.75%
SIMPLE INTEREST, SI = (3875 – 2500) = RS.1375
PRINCIPAL, P = RS. 2500
TIME, T = 4 YEARS
R = ?
R=100×SI/PT=100×13752/500×4
=100×1375/10000=13.75%
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