12th Grade > Chemistry
REDOX REACTIONS MCQs
Total Questions : 29
| Page 2 of 3 pages
Answer: Option A. -> Oxidising agent
:
A
In this reactionH2Oacts as oxidising agent.
:
A
In this reactionH2Oacts as oxidising agent.
Answer: Option D. -> HOCl
:
D
HClO is the strongest oxidising agent. The correct order of oxidising power is
+1HClO>+3HClO2>+5HClO3>+7HClO4
:
D
HClO is the strongest oxidising agent. The correct order of oxidising power is
+1HClO>+3HClO2>+5HClO3>+7HClO4
Answer: Option D. -> An oxidant, a reductant and an acid
:
D
As an oxidant:
2Fe2+(aq)+H2O2+2H+(aq)⟶2Fe3+(aq)+2H2O(l)
As as reductant (these reactions are apt to produce O2 in lab):
NaOCl+H2O2⟶O2+NaCl+H2O
2KMnO4+3H2O2⟶2MnO2+2KOH+2H2O+3O2
Hydrogen peroxide is a weak acid, forming hydroperoxide or peroxide salts with many metals.
:
D
As an oxidant:
2Fe2+(aq)+H2O2+2H+(aq)⟶2Fe3+(aq)+2H2O(l)
As as reductant (these reactions are apt to produce O2 in lab):
NaOCl+H2O2⟶O2+NaCl+H2O
2KMnO4+3H2O2⟶2MnO2+2KOH+2H2O+3O2
Hydrogen peroxide is a weak acid, forming hydroperoxide or peroxide salts with many metals.
Answer: Option A. -> 5
:
A
When you account for the change in the oxidation number of Manganese on either side:
MnO−4+8H++5e−⟶Mn2++4H2O
x = 5.
:
A
When you account for the change in the oxidation number of Manganese on either side:
MnO−4+8H++5e−⟶Mn2++4H2O
x = 5.
Answer: Option B. -> It acts as both oxidising and reducing agent
:
B
H2O2 is amphoteric in nature.It acts as both oxidizing and reducing agent depending on reactions. For example, when reacted with PbS, it acts as an oxidizing agent whereas it acts as areducing agent when reacting with HOCl
:
B
H2O2 is amphoteric in nature.It acts as both oxidizing and reducing agent depending on reactions. For example, when reacted with PbS, it acts as an oxidizing agent whereas it acts as areducing agent when reacting with HOCl
Answer: Option B. -> SO2
:
B
In SO2, sulphur has a +4 oxidation state. In H2SO4, Sulphur exhibits its highest oxidation state of +6.
On the other hand - in H2S, sulphur exists in its lowest -2 oxidation state. Thus, we can surmise
that SO2 could act as both an oxidising agent as well as a reducing agent. Nitrogen exhibits its highest oxidation
state of +5 in HNO3.
:
B
In SO2, sulphur has a +4 oxidation state. In H2SO4, Sulphur exhibits its highest oxidation state of +6.
On the other hand - in H2S, sulphur exists in its lowest -2 oxidation state. Thus, we can surmise
that SO2 could act as both an oxidising agent as well as a reducing agent. Nitrogen exhibits its highest oxidation
state of +5 in HNO3.
Answer: Option D. -> I−
:
D
I−act as a more reducing agent than other ions.
:
D
I−act as a more reducing agent than other ions.
Answer: Option D. -> CrO2Cl2
:
D
In MnO−4, Mn is in +7 oxidation state.
Likewise, inCr(CN)3−6 Chromium exhibits +3 oxidation state.
As forNiF2−6, Nickel shows +4oxidation state.
What will be the oxidation number of Cr in CrO2Cl2?
We apply the rules for assigning oxidation number:
x−4−2=0
Solving,x=+6
:
D
In MnO−4, Mn is in +7 oxidation state.
Likewise, inCr(CN)3−6 Chromium exhibits +3 oxidation state.
As forNiF2−6, Nickel shows +4oxidation state.
What will be the oxidation number of Cr in CrO2Cl2?
We apply the rules for assigning oxidation number:
x−4−2=0
Solving,x=+6
Latest Videos
Latest Test Papers
Login With Google
Old way of Login
Login With Email