Ratio And Proportion(Quantitative Aptitude ) Questions and answers for exam Preparation

Quantitative Aptitude

RATIO AND PROPORTION MCQs

Ratio & Proportion, Ratio, Proportion

Total Questions : 895 | Page 57 of 90 pages

A sum of money is to be distributed among A, B, C, D in the proportion of 5 : 2 : 4 : 3. If C gets Rs. 1000 more than D, what is B's share?

Rs. 500
Rs. 1500
Rs. 2000
None of these

Discuss Question

Answer: Option C. -> Rs. 2000

Let the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively.

Then, 4x - 3x = 1000

x = 1000.

B's share = Rs. 2x = Rs. (2 x 1000) = Rs. 2000.

Question 562.

Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the ratio of increased seats?

2 : 3 : 4
6 : 7 : 8
6 : 8 : 9
None of these

Discuss Question

Answer: Option A. -> 2 : 3 : 4

Originally, let the number of seats for Mathematics, Physics and Biology be 5x, 7x and 8x respectively.

Number of increased seats are (140% of 5x), (150% of 7x) and (175% of 8x).

140
x 5x

,

150
x 7x

and

175
x 8x

100
100
100

7x,
21x
and 14x.
2

The required ratio = 7x :
21x
: 14x
2

14x : 21x : 28x

2 : 3 : 4.

Question 563.

In a mixture 60 litres, the ratio of milk and water 2 : 1. If this ratio is to be 1 : 2, then the quantity of water to be further added is:

20 litres
30 litres
40 litres
60 litres

Discuss Question

Answer: Option D. -> 60 litres

Quantity of milk =

60 x
2
litres = 40 litres.
3

Quantity of water in it = (60- 40) litres = 20 litres.

New ratio = 1 : 2

Let quantity of water to be added further be x litres.

Then, milk : water =

40

.
20 + x

Now,

40

=
1
20 + x
2

20 + x = 80

x = 60.

Quantity of water to be added = 60 litres.

Question 564.

Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:

2 : 5
3 : 5
4 : 5
6 : 7

Discuss Question

Answer: Option C. -> 4 : 5

Let the third number be x.

Then, first number = 120% of x =
120x
=
6x
100
5

Second number = 150% of x =
150x
=
3x
100
2

Ratio of first two numbers =

6x
:
3x

= 12x : 15x = 4 : 5.
5
2

Question 565.

The ratio of the number of boys and girls in a college is 7 : 8. If the percentage increase in the number of boys and girls be 20% and 10% respectively, what will be the new ratio?

8 : 9
17 : 18
21 : 22
Cannot be determined

Discuss Question

Answer: Option C. -> 21 : 22

Originally, let the number of boys and girls in the college be 7x and 8x respectively.

Their increased number is (120% of 7x) and (110% of 8x).

120
x 7x

and

110
x 8x

100
100

42x
and
44x
5
5

The required ratio =

42x
:
44x

= 21 : 22.
5
5

Question 566.

If 0.75 : x :: 5 : 8, then x is equal to:

1.12
1.2
1.25
1.30

Discuss Question

Answer: Option B. -> 1.2

(x x 5) = (0.75 x 8) x =

6

= 1.20
5

Question 567.

The sum of three numbers is 98. If the ratio of the first to second is 2 :3 and that of the second to the third is 5 : 8, then the second number is:

Discuss Question

Answer: Option B. -> 30

Let the three parts be A, B, C. Then,

A : B = 2 : 3 and B : C = 5 : 8 =

5 x
3

:

8 x
3

= 3 :
24
5
5
5

A : B : C = 2 : 3 :
24
= 10 : 15 : 24
5

B =

98 x
15

= 30.
49

Question 568.

Salaries of Ravi and Sumit are in the ratio 2 : 3. If the salary of each is increased by Rs. 4000, the new ratio becomes 40 : 57. What is Sumit's salary?

Rs. 17,000
Rs. 20,000
Rs. 25,500
Rs. 38,000

Discuss Question

Answer: Option D. -> Rs. 38,000

Let the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively.

Then,
2x + 4000
=
40
3x + 4000
57

57(2x + 4000) = 40(3x + 4000)

6x = 68,000

3x = 34,000

Sumit's present salary = (3x + 4000) = Rs.(34000 + 4000) = Rs. 38,000.

Question 569.

If Rs. 782 be divided into three parts, proportional to : : , then the first part is:

Rs. 182
Rs. 190
Rs. 196
Rs. 204

Discuss Question

Answer: Option D. -> Rs. 204

Given ratio = : : = 6 : 8 : 9.

1^st part = Rs.

782 x
6

= Rs. 204
23

Question 570. Find the numbers which are in the ratio 3:2:4 such that the sum of the first and the second added to the difference of the third and the second is 21.

12, 8, 16
6, 4, 8
9, 6, 24
9, 6, 12
None of these

Discuss Question

Answer: Option D. -> 9, 6, 12

Let the numbers be a, b and c.
a:b:c = 3:2:4
Given, (a + b) + (c - b) = 21
=> a + c = 21
=> 3x + 4x = 21 => x = 3
a, b, c are 3x, 2x, 4x
a, b, c are 9, 6, 12.