Quantitative Aptitude
PROBABILITY MCQs
Probability, Probability I
Total Questions : 775
| Page 8 of 78 pages
Answer: Option D. -> 0.8
:
D
Total number of balls played = 30
Number of balls in which the batsman hit a boundary= 6
Number of balls in which he didnot hit a boundary
= 30 – 6
= 24
∴Probability of not hitting a boundary=Number of balls in which he does not hit a boundaryTotal number of balls played=2430=0.8
:
D
Total number of balls played = 30
Number of balls in which the batsman hit a boundary= 6
Number of balls in which he didnot hit a boundary
= 30 – 6
= 24
∴Probability of not hitting a boundary=Number of balls in which he does not hit a boundaryTotal number of balls played=2430=0.8
Answer: Option C. -> 0.08
:
C
Number of parts exiting an assembly line which are bad(defective) = 8
Total number of parts passing the assembly line = 100
Probability of part being defective =Number of defective partsTotal number of parts
Probability of a part being defective =8100=0.08
:
C
Number of parts exiting an assembly line which are bad(defective) = 8
Total number of parts passing the assembly line = 100
Probability of part being defective =Number of defective partsTotal number of parts
Probability of a part being defective =8100=0.08
Answer: Option C. -> 0.325
:
C
Number of times 2 or 4 appears when a die was rolled = 175 + 150 = 325
Total number of times a die is thrown = 1000
Probability of getting a 2 or a 4 =number of times 2 or 4 appearstotal number of times a die is thrown
⇒Probability=3251000=0.325
:
C
Number of times 2 or 4 appears when a die was rolled = 175 + 150 = 325
Total number of times a die is thrown = 1000
Probability of getting a 2 or a 4 =number of times 2 or 4 appearstotal number of times a die is thrown
⇒Probability=3251000=0.325
Answer: Option D. -> 0.7
:
D
Total number of students in a class = 50
Number of students who passed an examination = 35
Probability that a student passed the exam =Number of students who passed an examinatioTotal number of students in a class
Probability that a student passed the exam = 3550=0.7.
:
D
Total number of students in a class = 50
Number of students who passed an examination = 35
Probability that a student passed the exam =Number of students who passed an examinatioTotal number of students in a class
Probability that a student passed the exam = 3550=0.7.
Answer: Option D. -> 136
:
D
Total number of outcomes when two dice are thrown =
(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6) = 36.
Sum of 12 = (6,6)
Therefore, Probability of getting a sum of 12 = 136.
:
D
Total number of outcomes when two dice are thrown =
(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6) = 36.
Sum of 12 = (6,6)
Therefore, Probability of getting a sum of 12 = 136.
Question 76. Two kids Goutham and Pavani are fighting for coins. Finally, Goutham won and stole a coin from Pavani's pocket which has four different coins ( a 1 rupee coin, a 2 rupee coin, a 5 rupee coin, a 10 rupee coin). What are the total number of possible outcomes when Goutham tried to steal a coin?
Answer: Option A. -> 4
:
A
As there are four different coins in Pavani's pocket, so there are 4 possible ways in which Goutham can steal a coin i.e. 1 rupee coin, 2 rupee coin, 5 rupee coin, 10 rupee coin. Therefore a total number of possible outcomes are 4.
:
A
As there are four different coins in Pavani's pocket, so there are 4 possible ways in which Goutham can steal a coin i.e. 1 rupee coin, 2 rupee coin, 5 rupee coin, 10 rupee coin. Therefore a total number of possible outcomes are 4.
Answer: Option C. -> A multiple of 7
:
C
When you throw an unbiased die, the outcomes are1, 2, 3, 4, 5 and 6 and none of them are multiple of 7.
:
C
When you throw an unbiased die, the outcomes are1, 2, 3, 4, 5 and 6 and none of them are multiple of 7.
Answer: Option B. -> 16
:
B
Suppose a dieis rolled, the possible outcomes are1, 2, 3, 4, 5, 6. Each number appearing on the face of adiedoes not affect the other numbers.Each number has aprobability of 16 to occur when a die is rolled. It does not depend on the number that it shows.
For instance, the probability that we roll a die and 2 comes is 16, since there is only single 2 on the cube.
:
B
Suppose a dieis rolled, the possible outcomes are1, 2, 3, 4, 5, 6. Each number appearing on the face of adiedoes not affect the other numbers.Each number has aprobability of 16 to occur when a die is rolled. It does not depend on the number that it shows.
For instance, the probability that we roll a die and 2 comes is 16, since there is only single 2 on the cube.
Answer: Option A. -> 57
:
A
Given, it had rained 5 out of 7 days.
i.e., Number of rainy days = 5
Total number ofdays = 7
Then,
Probability=Number of rainy daysTotal number of days=57
:
A
Given, it had rained 5 out of 7 days.
i.e., Number of rainy days = 5
Total number ofdays = 7
Then,
Probability=Number of rainy daysTotal number of days=57
Answer: Option D. -> there is 82% chance that India will win but we cannot say that India will definitely win.
:
D
It is 82% likely that India will win the match means that there is 82% chance that India is winning the match. There is still 18% uncertainty that India will not win. In terms of probability, the probability of India winning will be 0.82. So India may or may not win. Therefore, we cannot say that India will definitely win.
:
D
It is 82% likely that India will win the match means that there is 82% chance that India is winning the match. There is still 18% uncertainty that India will not win. In terms of probability, the probability of India winning will be 0.82. So India may or may not win. Therefore, we cannot say that India will definitely win.