Quantitative Aptitude
PROBABILITY MCQs
Probability, Probability I
Total Questions : 775
| Page 6 of 78 pages
:
Winning or losing a game are complementary events. We know that, for complementary events, P(A) + P(notA) = 1.
Thus, if P(winning) = 25
Then, P(losing) = 1 - 25
⇒ P(losing) = 35 = 0.6.
Answer: Option B. -> 717
:
B
The total number of possibleoutcomes(counting of the cards from 1to 17) = 17
Favourable outcomes are3, 6, 7, 9, 12, 14 and 15.
∴ No. offavourable outcomes = 7
Let E be the event of getting a multiple of 3 or 7.
∴ Probability P(E) = Number of outcomes favorable to ENumber of all possible outcomes of the experiment=717
:
B
The total number of possibleoutcomes(counting of the cards from 1to 17) = 17
Favourable outcomes are3, 6, 7, 9, 12, 14 and 15.
∴ No. offavourable outcomes = 7
Let E be the event of getting a multiple of 3 or 7.
∴ Probability P(E) = Number of outcomes favorable to ENumber of all possible outcomes of the experiment=717
Answer: Option C. -> 0.85
:
C
Given, P (A) = 0.15
As, P(A) and P(not A) are complementary events, P(A) + P(not A) = 1
P (not A) = 1 – P (A) = 1 – 0.15 = 0.85
:
C
Given, P (A) = 0.15
As, P(A) and P(not A) are complementary events, P(A) + P(not A) = 1
P (not A) = 1 – P (A) = 1 – 0.15 = 0.85
Answer: Option A. -> r2R2
:
A
Area of board = πR2
Area of bull's eye = πr2
Here, weshalluse the concept of geometric probability as the number of outcomes are not finite.
The probability of hitting the bull's eye
=Area of the bull's eyeArea of the board=π.r2π.R2 = r2R2
:
A
Area of board = πR2
Area of bull's eye = πr2
Here, weshalluse the concept of geometric probability as the number of outcomes are not finite.
The probability of hitting the bull's eye
=Area of the bull's eyeArea of the board=π.r2π.R2 = r2R2
Answer: Option B. -> P
:
B
The number of times in a period of 12 hours the hands of the clock will form an acute angle will be the same as that for obtuse angle. So, you would think that the probability is 12. But if you take into account the number of times when the hands are alligned ( 0∘), hands are at right angles and hands are facing in opposite directions ( 180∘), then the probability would be slightly less than 0.5.
:
B
The number of times in a period of 12 hours the hands of the clock will form an acute angle will be the same as that for obtuse angle. So, you would think that the probability is 12. But if you take into account the number of times when the hands are alligned ( 0∘), hands are at right angles and hands are facing in opposite directions ( 180∘), then the probability would be slightly less than 0.5.
Answer: Option C. -> 985
:
C
Total number of pages in the book = 85
Favorable outcomes are:8, 17, 26, 35, 44, 53, 62, 71, 80.
∴ No. of favorable outcomes = 9
Let E be the event of gettingsum of the digits on the page is 8.
Probability P(E) = Number of outcomes favorable to ENumber of all possible outcomes of the experiment=985
:
C
Total number of pages in the book = 85
Favorable outcomes are:8, 17, 26, 35, 44, 53, 62, 71, 80.
∴ No. of favorable outcomes = 9
Let E be the event of gettingsum of the digits on the page is 8.
Probability P(E) = Number of outcomes favorable to ENumber of all possible outcomes of the experiment=985
Answer: Option D. -> 120
:
D
Numbers divisible by 4 and 5 both = 20, 40, 60, 80, 100.
Hence P = Favourable outcomesTotal outcomes =5100= 120
= 120
:
D
Numbers divisible by 4 and 5 both = 20, 40, 60, 80, 100.
Hence P = Favourable outcomesTotal outcomes =5100= 120
= 120
Answer: Option A. -> 18
:
A
If a coin tossed thrice, the total possible outcomes = {HHH, HHT, HTT, HTH, THH, TTH, THT, TTT}.
= 8
Number of cases of getting tail each time = {TTT}
= 1
The probability of getting tail each time = Number of favourable casestotal possible outcomes
= 18
:
A
If a coin tossed thrice, the total possible outcomes = {HHH, HHT, HTT, HTH, THH, TTH, THT, TTT}.
= 8
Number of cases of getting tail each time = {TTT}
= 1
The probability of getting tail each time = Number of favourable casestotal possible outcomes
= 18
:
The sum of the probabilities of all the elementary events of an experiment is 1.
Answer: Option A. -> True
:
A
There are 4 red marbles out of a total of 12 marbles. So, the probability of drawing red is 412= 13.
:
A
There are 4 red marbles out of a total of 12 marbles. So, the probability of drawing red is 412= 13.