Perimeter Area And Volume(5th Grade > Mathematics ) Questions and answers for exam Preparation

5th Grade > Mathematics

PERIMETER AREA AND VOLUME MCQs

Total Questions : 40 | Page 2 of 4 pages

Question 11. Ali runs along the sides of a square park whose side is 10 m long. Find the distance covered by Ali if he runs around the park twice.

40 m
60 m
80 m
100 m

Discuss Question

Answer: Option C. -> 80 m
:
C
Given: Side of the Square = 10 m
Ali isrunning along theboundary of the park.
This implies thatthe distance covered by him will be equal to the perimeter of the park.
Perimeter of a square = 4

\times

Side

\Rightarrow

Perimeter of the square park = 4

\times

10 m
= 40 m
Distance covered by Ali in two rounds of the park =2

\times

Perimeter of the park
= 2

\times

40 m
= 80 m
Therefore, distance covered by Ali is 80 m.

Question 12. Calculate the area bounded by the square shown below:

6 cm2
12 cm2
24 cm2
36 cm2

Discuss Question

Answer: Option D. -> 36 cm2
:
D
Given:
side of the square is

6 c m

.
area of square =

s i d e^{2}

∴

Area of the given figure =

(6 c m)^{2}

36 c m^{2}

Question 13. Volume of a cube with side 4 cm is:

8 cm3
16 cm3
32 cm3
64 cm3

Discuss Question

Answer: Option D. -> 64 cm3
:
D
Given: Length of the side = 4 cm
Volume of the cube

= S i d e \times S i d e \times S i d e

= 4 c m \times 4 c m \times 4 c m

= 64 c m^{3}

Question 14. Length and breadth of a rectangle are 10 cm and 5 cm. Find its area.

15 cm
15 cm2
2 cm
50 cm2

Discuss Question

Answer: Option D. -> 50 cm2
:
D
Given: Length of the rectangle = 10 cm
Breadth of the rectangle = 5 cm
Area of a rectangle = Length

\times

Breadth
=

10 c m \times 5 c m

50 c m^{2}

Therefore, area of the given rectangle is

50 c m^{2}

Question 15. If the dimensions of a brick is

20 c m \times 10 c m \times 5 c m

, then the volume of two such bricks will be ____

c m^{3}

1000
2000
3000
4000

Discuss Question

Answer: Option B. -> 2000
:
B
Given: Dimensions of a brick is

20 c m \times 10 c m \times 5 c m

.
Volume of the brick

= l e n g t h \times b r e a d t h \times h e i g h t = 20 c m \times 10 c m \times 5 c m = 1000 c m^{3}

Volume of two bricks

= 2 \times 1000 c m^{3} = 2000 c m^{3}

Question 16. Find the perimeter of the triangle given below.

150 cm
90.8 cm
170 cm
90.08 cm

Discuss Question

Answer: Option C. -> 170 cm
:
C
We know that 1 m = 100 cm

\Rightarrow

0. 8 m = 0.8

\times

100 cm = 80 cm
Perimeter = Sum of allsides = AB + BC +AC

\Rightarrow

Perimeter = 50 cm + 40 cm + 80 cm= 170 cm

Question 17. If the area of a rectangle is 63

c m^{2}

and its breadth is 7 cm, then the length of the rectangle is:

6 cm
7 cm
8 cm
9 cm

Discuss Question

Answer: Option D. -> 9 cm
:
D
Given:
Breadth of a rectangle = 7 cm
Area of the rectangle = 63

c m^{2}

Area ofrectangle = Length

\times

Breadth

\Rightarrow

Length =

\frac{A r e a}{B r e a d t h}

\Rightarrow

Length =

\frac{63 c m^{2}}{7 c m} = 9 c m

Question 18. If the perimeter of a square is 40 cm, then find the length of its side.

5 cm
10 cm
160 cm
80 cm

Discuss Question

Answer: Option B. -> 10 cm
:
B
Given: Perimeter of the square = 40 cm
Perimeter of a square =

4 \times S i d e

\Rightarrow

4 \times S i d e = 40 c m

\Rightarrow

S i d e = 10 c m

∴

If the perimeter of a square is 40 cm, then the length of its side will be 10 cm.

Question 19. If the dimensions of a box is

6 m \times 4 m \times 5 m

, then its volume is:

120 m3
158 m3
132 m3
128 m3

Discuss Question

Answer: Option A. -> 120 m3
:
A

V o l u m e o f t h e b o x = L e n g t h \times B r e a d t h \times H e i g h t

= 6 m \times 4 m \times 5 m

= 120 m^{3}

Therefore, volume of the box will be

120 m^{3}

Question 20. A rectangle is formed by keeping two squares next to each other. The length of the sides of each square is 10 cm.
What is the area of the rectangle formed by these two squares?

100 cm2
200 cm2
300 cm2
400 cm2

Discuss Question

Answer: Option B. -> 200 cm2
:
B
Given: The length of the sides of each square is 10 cm.
For the rectangle formed:
Length= 10 cm + 10 cm = 20 cm
Breadth = 10 cm
Area of therectangle = Length