12th Grade > Physics
OPTICS MCQs
Wave Optics, Ray Optics Refraction, Ray Optics Fundamentals, Ray Optics Curved Surface Refraction, Ray Optics Curved Mirrors
Total Questions : 111
| Page 11 of 12 pages
Answer: Option A. -> 1u versus 1v
:
A
For a lens 1f=1v−1u⇒1v=1u+1f....(i)
Also m=f−vf=1−vf⇒m=(−1f)v+1...(ii)
On comparing equations (i) and (ii) with y =mx +c.
It is clear that relationship between 1vvs1uand m vs v is linear.
:
A
For a lens 1f=1v−1u⇒1v=1u+1f....(i)
Also m=f−vf=1−vf⇒m=(−1f)v+1...(ii)
On comparing equations (i) and (ii) with y =mx +c.
It is clear that relationship between 1vvs1uand m vs v is linear.
Answer: Option D. -> 15 cm
:
D
Image will be formed at infinity if object is placed at focus of the lens i.e., at 20 cm from thelens. Hence,
Shift = 25−20=(1−1μ)t
or 5=(1−11.5)t
or t=5×1.50.5=15cm
:
D
Image will be formed at infinity if object is placed at focus of the lens i.e., at 20 cm from thelens. Hence,
Shift = 25−20=(1−1μ)t
or 5=(1−11.5)t
or t=5×1.50.5=15cm
Answer: Option D. -> 7.5 cm
:
D
R=−30cm⇒f=−15cm
O = +2.5 cm, u =-10 cm
By mirror formula 1−15=1v+1(−10)⇒v=30cm.
Also IO=−vu⇒I(+2.5)=−30(−10)⇒I=7.5cm.
:
D
R=−30cm⇒f=−15cm
O = +2.5 cm, u =-10 cm
By mirror formula 1−15=1v+1(−10)⇒v=30cm.
Also IO=−vu⇒I(+2.5)=−30(−10)⇒I=7.5cm.
Answer: Option D. -> 38∘
:
D
Deviation produce by the prism isδ=i+e–A=53∘+37∘–A=90∘–A
For angle of incidence 50∘ angle of emergence will be grater than 37∘ and also
i + e < 90∘
:
D
Deviation produce by the prism isδ=i+e–A=53∘+37∘–A=90∘–A
For angle of incidence 50∘ angle of emergence will be grater than 37∘ and also
i + e < 90∘
Answer: Option B. -> 7.5 cm
:
B
f=-15 cm, m=+2(Positive because image is virtual)
∵m=−vu⇒v=−2u By using mirror formula
1−15=1(−2u)+1u⇒u=−7.5cm
:
B
f=-15 cm, m=+2(Positive because image is virtual)
∵m=−vu⇒v=−2u By using mirror formula
1−15=1(−2u)+1u⇒u=−7.5cm
Answer: Option A. -> 0.4 cm away from the mirror
:
A
Mirror formula
1f=1v+1u⇒1f=1−20+1(−10)⇒f=203cm.
If object moves towards the mirror by 0.1 cm then. u =(10-0.1)=9.9 cm.
Hence again from mirror formula 1−203=1v+1−9.9⇒v′=20.4cm
i.e. image shifts away from the mirror by 0.4 cm.
:
A
Mirror formula
1f=1v+1u⇒1f=1−20+1(−10)⇒f=203cm.
If object moves towards the mirror by 0.1 cm then. u =(10-0.1)=9.9 cm.
Hence again from mirror formula 1−203=1v+1−9.9⇒v′=20.4cm
i.e. image shifts away from the mirror by 0.4 cm.
Answer: Option B. -> Concave mirror of radius of curvature 12 cm
:
B
Erect and enlarged image can produced by concave mirror.
IO=ff−u⇒+3+1=ff=(−4)⇒f=−6cm⇒R=2f=−12cm
:
B
Erect and enlarged image can produced by concave mirror.
IO=ff−u⇒+3+1=ff=(−4)⇒f=−6cm⇒R=2f=−12cm