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12th Grade > Physics

OPTICS MCQs

Wave Optics, Ray Optics Refraction, Ray Optics Fundamentals, Ray Optics Curved Surface Refraction, Ray Optics Curved Mirrors

Total Questions : 111 | Page 11 of 12 pages
Question 101. The graph shows how the magnification m produced by a convex thin lens varies with image distance v. What was the focal length of the used                            
[DPMT 1995]

The Graph Shows How The Magnification M Produced By A Convex...
 Discuss Question
Answer: Option A. ->
:
D
The Graph Shows How The Magnification M Produced By A Convex...
Question 102. The object distance u, the image distance v and the magnification m in a lens follow certain linear relations.  These are
  1.    1u versus 1v
  2.    m versus u
  3.    u versus v
  4.    m versus 1u
 Discuss Question
Answer: Option A. -> 1u versus 1v
:
A
For a lens 1f=1v1u1v=1u+1f....(i)
Also m=fvf=1vfm=(1f)v+1...(ii)
On comparing equations (i) and (ii) with y =mx +c.
It is clear that relationship between 1vvs1uand m vs v is linear.
Question 103. A point object is placed at a distance of 25 cm from a convex lens of focal length 20 cm. If a glass slab of thickness t and refractive index 1.5 is inserted between the lens and the object the image is formed at infinity. The thickness t is
 
  1.    10 cm
  2.    5 cm
  3.    20 cm
  4.    15 cm
 Discuss Question
Answer: Option D. -> 15 cm
:
D
Image will be formed at infinity if object is placed at focus of the lens i.e., at 20 cm from thelens. Hence,
Shift = 2520=(11μ)t
or 5=(111.5)t
or t=5×1.50.5=15cm
Question 104. An object 2.5 cm high is placed at a distance of 10 cm   from a concave mirror of radius of curvature 30 cm  The size of the image is
  1.    9.2 cm 
  2.    10.5 cm 
  3.    5.6 cm
  4.    7.5 cm 
 Discuss Question
Answer: Option D. -> 7.5 cm 
:
D
R=30cmf=15cm
O = +2.5 cm, u =-10 cm
By mirror formula 115=1v+1(10)v=30cm.
Also IO=vuI(+2.5)=30(10)I=7.5cm.
Question 105. A ray incident at an angle 53 on a prism and emerges at an angle of 37 as shown in figure. If the angle of incidence is made 50 then possible value of the angle of emergence is
A Ray Incident At An Angle 53∘ On A Prism And Emerges At A...
  1.    35∘
  2.    42∘
  3.    40∘
  4.    38∘
 Discuss Question
Answer: Option D. -> 38∘
:
D
Deviation produce by the prism isδ=i+eA=53+37A=90A
For angle of incidence 50 angle of emergence will be grater than 37 and also
i + e < 90
Question 106. An object of size 7.5cm is placed in front of a convex mirror of radius of curvature 25cm at a distance of 40cm The size of the image should be
  1.    2.3cm
  2.    1.78cm
  3.    1cm
  4.    0.8cm
 Discuss Question
Answer: Option B. -> 1.78cm
:
B
An Object Of Size 7.5cm Is Placed In Front Of A Convex Mirro...
Question 107. A concave mirror of focal length 15 cm forms an image having twice the linear dimensions of the object. The position of the object when the image is virtual will be
  1.    22.5 cm ​
  2.    7.5 cm 
  3.    30 cm
  4.    45 cm 
 Discuss Question
Answer: Option B. -> 7.5 cm 
:
B
f=-15 cm, m=+2(Positive because image is virtual)
m=vuv=2u By using mirror formula
115=1(2u)+1uu=7.5cm
Question 108. A concave mirror of focal length 100 cm is used to obtain the image of the sun which subtends an angle of 30'. The diameter of the image of the sun will be
  1.    1.74 cm
  2.    0.87 cm
  3.    0.435 cm
  4.    100 cm
 Discuss Question
Answer: Option B. -> 0.87 cm
:
B
Diameter of image of sun d=fθ
d=100×(3060)×π180
d=0.87cm.
A Concave Mirror Of Focal Length 100 Cm Is Used To Obtain Th...
Question 109. A point object is placed at a distance of 10 cm and its real image is formed at a distance of 20 cm from a concave mirror. If the object is moved by 0.1 cm towards the mirror, the image will shift by about
  1.    0.4 cm away from the mirror
  2.    0.4 cm towards the mirror
  3.    0.8 away from the mirror
  4.    0.8 cm towards the mirror
 Discuss Question
Answer: Option A. -> 0.4 cm away from the mirror
:
A
Mirror formula
1f=1v+1u1f=120+1(10)f=203cm.
If object moves towards the mirror by 0.1 cm then. u =(10-0.1)=9.9 cm.
Hence again from mirror formula 1203=1v+19.9v=20.4cm
i.e. image shifts away from the mirror by 0.4 cm.
Question 110. An object 1 cm tall is placed 4 cm infront of a mirror. In order to produce an upright image of 3 cm height one needs a
  1.    Convex mirror of radius of curvature 12 cm
  2.    Concave mirror of radius of curvature 12 cm
  3.    Concave mirror of radius of curvature 4 cm
  4.    Plane mirror of height 12 cm
 Discuss Question
Answer: Option B. -> Concave mirror of radius of curvature 12 cm
:
B
Erect and enlarged image can produced by concave mirror.
IO=ffu+3+1=ff=(4)f=6cmR=2f=12cm

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