Reasoning Aptitude
NUMBER SERIES COMPLETION MCQs
Total Questions : 501
| Page 48 of 51 pages
Answer: Option A. -> 101
The sequence is (14)2 , (13)2 , (12)2 , (11)2 , (10)2 ..........So, 101 is wrong and must be replaced by (10)2 i.e., 100
The sequence is (14)2 , (13)2 , (12)2 , (11)2 , (10)2 ..........So, 101 is wrong and must be replaced by (10)2 i.e., 100
Answer: Option C. -> 24
The correct pattern is ÷ 12, ÷ 10, ÷ 8, ÷ 6,.........So, 24 is wrong and must be replaced by (48 ÷ 6) i.e., 8.
The correct pattern is ÷ 12, ÷ 10, ÷ 8, ÷ 6,.........So, 24 is wrong and must be replaced by (48 ÷ 6) i.e., 8.
Answer: Option C. -> 550
The correct pattern is ×2, ×4, ×2, ×4 . . . . . .
So, 550 is wrong and must be replaced by (320 × 2) i.e., 640
The correct pattern is ×2, ×4, ×2, ×4 . . . . . .
So, 550 is wrong and must be replaced by (320 × 2) i.e., 640
Answer: Option D. -> 64
The term of the series are (12 + 1)(22 + 1)(32 + 1)(42 + 1)(52 + 1)(62 + 1)(72 + 1),..............So, 64 is wrong and must be replaced by (82 + 1) i.e., 65
The term of the series are (12 + 1)(22 + 1)(32 + 1)(42 + 1)(52 + 1)(62 + 1)(72 + 1),..............So, 64 is wrong and must be replaced by (82 + 1) i.e., 65
Answer: Option A. -> 36
The correct sequence is 52 , 72 , 92 , 112 , 132 , 152.So, 36 is wrong.
The correct sequence is 52 , 72 , 92 , 112 , 132 , 152.So, 36 is wrong.
Answer: Option B. -> 39
The correct pattern is × 2 + 1.So, 39 is wrong and must be replaced by (15 × 2 + 1) i.e., 31.
The correct pattern is × 2 + 1.So, 39 is wrong and must be replaced by (15 × 2 + 1) i.e., 31.
Answer: Option A. -> 8
Each term at an even place in the series is the product of its two adjacent terms.Thus, if the missing term be x, then we have :7 × x = 56 or x = 56 ÷ 7 = 8
Each term at an even place in the series is the product of its two adjacent terms.Thus, if the missing term be x, then we have :7 × x = 56 or x = 56 ÷ 7 = 8
Answer: Option A. -> 10, 10
Let the missing terms of the series be x1 and x2.Thus, the sequence 20, 20, 19, 16, 17, 13, 14, 11. x1, x2 is a combination of two series:I. 20, 19, 17, 14, x1 and II. 20, 16, 13, 11, x2The pattern in I is - 1, - 2, - 3,..............So, missing term, x1= 14 - 4 = 10The pattern in II is - 4, - 3, - 2,.......... So,missing term, x2 = 11 - 1 = 10
Let the missing terms of the series be x1 and x2.Thus, the sequence 20, 20, 19, 16, 17, 13, 14, 11. x1, x2 is a combination of two series:I. 20, 19, 17, 14, x1 and II. 20, 16, 13, 11, x2The pattern in I is - 1, - 2, - 3,..............So, missing term, x1= 14 - 4 = 10The pattern in II is - 4, - 3, - 2,.......... So,missing term, x2 = 11 - 1 = 10
Answer: Option C. -> 50
The sum of any three consecutive terms of the series gives the next term,So, missing number = 8 + 15 + 27 = 50
The sum of any three consecutive terms of the series gives the next term,So, missing number = 8 + 15 + 27 = 50
Answer: Option C. -> 55
The given sequence is a combination of two series:I. 45, 47, 49, 51, 53 andII. 54, ?, 56, 57Clearly, II. consists of consecutive natural numbers, starting from 54.so, missing term = 55.
The given sequence is a combination of two series:I. 45, 47, 49, 51, 53 andII. 54, ?, 56, 57Clearly, II. consists of consecutive natural numbers, starting from 54.so, missing term = 55.
Latest Videos
Latest Test Papers
Login With Google
Old way of Login
Login With Email