12th Grade > Physics
MECHANICAL PROPERTIES OF FLUIDS MCQs
Total Questions : 29
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Answer: Option C. -> 3
:
C
Apparent weight = V(ρ−σ)g = mρ(ρ−σ)g
where m = mass of the body,
ρ = density of the body
σ = density of water
If two bodies are in equilibrium then their apparent weight must be equal.
∴m1ρ1(ρ1−σ) = m2ρ2(ρ2−σ)
⇒369(9−1) = 48ρ2(ρ2−1)
By solving we get ρ2 = 3
:
C
Apparent weight = V(ρ−σ)g = mρ(ρ−σ)g
where m = mass of the body,
ρ = density of the body
σ = density of water
If two bodies are in equilibrium then their apparent weight must be equal.
∴m1ρ1(ρ1−σ) = m2ρ2(ρ2−σ)
⇒369(9−1) = 48ρ2(ρ2−1)
By solving we get ρ2 = 3
Answer: Option C. -> M[1ρ−1σ]
:
C
Volume of ice = Mρ, volume of water = Mσ
∴ Change in volume = Mρ−Mσ=M⟮1ρ−1σ⟯
:
C
Volume of ice = Mρ, volume of water = Mσ
∴ Change in volume = Mρ−Mσ=M⟮1ρ−1σ⟯
Answer: Option D. -> M(1−dd2)(1−dd1)
:
D
Let MO=mass of body in vacuum.
Apparent weight of the body in air = Apparent weight of standard weights in air
Actual weight of the body - upthrust due to displaced air
= Actual weight of the weights- upthrust due to displaced air
⇒M0g−⟮M0d1⟯dg=Mg−⟮Md2⟯dg⇒M0=M[1−dd2][1−dd1]
:
D
Let MO=mass of body in vacuum.
Apparent weight of the body in air = Apparent weight of standard weights in air
Actual weight of the body - upthrust due to displaced air
= Actual weight of the weights- upthrust due to displaced air
⇒M0g−⟮M0d1⟯dg=Mg−⟮Md2⟯dg⇒M0=M[1−dd2][1−dd1]
Question 24. A long cylindrical rod of radius R1 is placed co-axially inside a cylindrical tube of radius R2(>R1) filled withviscous liquid and pulled along the axis with a constant velocity. In steady state the velocity gradient (dvdr) depends on the distance from the common axis 'r' as proportional to
Answer: Option B. -> r−1
:
B
f=ηAdvdx=constη2πrldvdx=constdvdxα1r
:
B
f=ηAdvdx=constη2πrldvdx=constdvdxα1r
Question 25. Air is streaming past a horizontal air plane wing such that its speed is 120m/s over the upper surface and 90 m/s at the lower surface. If the density of air is 1.3 kg per metre3 and the wing is 10 m long and has an average width of 2 m, then the difference of the pressure on the two sides of the wing is
Answer: Option A. -> 4095.0 Pascal
:
A
From the Bernoulli's theorem
P1−P2=12ρ(v22−v21)=12×1.3×[(120)2−(90)2]
=4095N/m2 or Pascal
:
A
From the Bernoulli's theorem
P1−P2=12ρ(v22−v21)=12×1.3×[(120)2−(90)2]
=4095N/m2 or Pascal
Question 26. A spherical ballof radius 3.0×10−4m and density 104 kg/m3 falls freely under gravity through a distance h it before entering a tank of water (coefficient of viscosity = η = 9.8×10−6Nsm−2 and density = 103kg/m3. If after entering the water, the velocity of the ball does not change, find~h.(Take g =9.8 ms−2)
Answer: Option B. -> 1.65 km
:
B
Terminal velocity,
u=√2gh=2r2(ρ−σ)g9η⇒h=2gr4(ρ−r)281η2=1.65km
:
B
Terminal velocity,
u=√2gh=2r2(ρ−σ)g9η⇒h=2gr4(ρ−r)281η2=1.65km
Answer: Option C. -> 10%
:
C
Let the total volume of ice-berg is V and its density is ρ. If this ice-berg floats in water with volume Vin inside
it then Vinσg=Vρg⇒Vin=⟮ρσ⟯V [σ = density of water]
or Vout=V−Vin=⟮σ−ρσ⟯V
⇒VoutV=⟮σ−ρσ⟯=1000−9001000=110
∴Vout=10% of V
:
C
Let the total volume of ice-berg is V and its density is ρ. If this ice-berg floats in water with volume Vin inside
it then Vinσg=Vρg⇒Vin=⟮ρσ⟯V [σ = density of water]
or Vout=V−Vin=⟮σ−ρσ⟯V
⇒VoutV=⟮σ−ρσ⟯=1000−9001000=110
∴Vout=10% of V
Answer: Option B. -> Pure water and glass; glass and alcohol
:
B
Both liquids water and alcohol have same nature (i.e. wet the solid). Hence angle of contact for both is acute.
:
B
Both liquids water and alcohol have same nature (i.e. wet the solid). Hence angle of contact for both is acute.
Answer: Option D. -> Height of the liquid in the tubes A and C is the same
:
D
As cross-section areas of both the tubes A and C are same and tube is horizontal. Hence according to equation of continuity vA=vC and therefore according to Bernoulli's theorem PA=PC i.e. height of liquid is same in both the tubes A and C.
:
D
As cross-section areas of both the tubes A and C are same and tube is horizontal. Hence according to equation of continuity vA=vC and therefore according to Bernoulli's theorem PA=PC i.e. height of liquid is same in both the tubes A and C.