Reasoning Aptitude
MATHEMATICAL OPERATIONS MCQs
F ≤ M -- (i); M > R -- (ii); E ≥ F -- (iii)From (I) and (ii), no specific relation can be obtained between M and E. Similarly, no specific relation can be obtained between R and E.
M = K -- (i); D ≤ K -- (ii); R < K -- (iii)from (i) and (ii), we getM = K ≥ D => M ≥ DHence, either M > D (conclusion II) or M = D (conclusion I) is true.
H = K -- (i); T < H -- (ii); W ≤ T -- (iii)From (i), (ii) and (iii), we getK = H > T ≥ W => K > W (conclusion I) and T < K (conclusion II).
N > A -- (i); A < L -- (ii); F = N -- (iii)From (i) and (iii),we get:F = N > A => F > A (conclusion II). But no specific relation can be obtained between L and F. Hence, conclusion I is not necessarily true.
B < D -- (i); D > N -- (ii); N ≤ H -- (iii)From equations (ii) and (iii), we can't obtained any specific relation between H and D. Hence, conclusion I (H ≥ D) is not true. But conclusion II (H ≥ N) follows from equation (iii).
Combining all the equations, we getK ≥ M ≠R = T => M ≠TFrom this we can't get any specific relation between K and T. Hence, conclusion I is not true. Conclusion II is false since M ≠T.
B ≤ D -- (i); D = M -- (ii); F > M -- (iii)From (i), (ii) and (iii), we get:F ≥ M = D ≥ B => B ≤ M and F > B (conclusion II).
M ≥ K -- (i); K > P -- (ii); P ≤ N -- (iii)combining (i) and (ii), we getM ≥ K > P -- (iv)From (iii) and (iv), no specific relation can be obtained between M and N. Hence, conclusion I (M > N) and conclusion II (M = N) are not true.
T ≤ M -- (i); M = Q -- (ii); Q ≤ R -- (iii)Combining (i) and (ii), we getM = Q ≥ T => Q > T (conclusion I)or Q + T (conclusion II)
Answer: (c)
- ⇒ ÷, + ⇒ x, ÷ ⇒ x, - ⇒ +,
From option (a), 19 + 5 - 4 x 2 ÷ 4 = 11
⇒ 19 x 5 ÷ 4 + 2 - 4 = 11
⇒ 95/4 + 2 - 4 ≠ 11
From option (b),
19 x 5 - 4 ÷ 2 + 4 = 16
⇒ 19 + 5 ÷ 4 - 2 x 4 = 16
⇒ 19 + 5/4 - 8 ≠ 16
From option (c),
19 ÷ 5 + 4 - 2 x 4 = 13
⇒ 19 - 5 x 4 ÷ 2 + 4 = 13
⇒ 19 - 5 x 2 + 4 = 13
⇒ 19 - 10 + 4 = 13
Therefore 13 = 13
As,we got our answer, there is no need to check option (d).