11th And 12th > Chemistry
IONIC EQUILIBRIUM MCQs
Total Questions : 30
| Page 1 of 3 pages
Answer: Option C. ->
HClO4
:
C
:
C
It is a HClO4
Answer: Option B. ->
CH3COO−
:
B
:
B
Because it is conjugate base of weak acid.
CH3COOH ⇌ CH3COO− + H+
Answer: Option A. ->
It gives OH− ion.
:
A
:
A
NaOH completely dissociates to give Na+ and OH− ions in water. Hence it is considered as a Strong base.
Answer: Option D. ->
ClO−4 is the conjugate base of HClO4
:
D
:
D
HClO4 + H2O ⇌ H3O+ + ClO−4
Here HClO4 and ClO−4 constitute conjugate acid and base pair.
Answer: Option D. ->
Is a electron pair acceptor
:
D
:
D
Lewis acids accept electron pairs
Answer: Option C. ->
Na2CO3
:
C
:
C
Na2CO3 + 2H2O ⇌ 2NaOH + H2CO3
Answer: Option B. ->
It is only slightly ionized
:
B
:
B
It is a weak electrolyte since slightly ionized.
Answer: Option A. ->
Basic
:
A
:
A
HCl = d
NaOH = 1.5 d
HCl in 10 ml of it = 10d36.5
NaOH in 10 ml of it =10× 1.5d40= 15d40
NaOH> HCl
Answer: Option A. ->
CO
:
A
:
A
CO doesn't have a vacant d-orbital.
Answer: Option C. ->
α = √KaC
:
C
:
C
According to the Ostwald's dilution formula α2 − Ka(1 − α)C. But for weak
electrolytes α is very small. So that (1 − α) can be taken as 1. So that α = √KaC.