5th Grade > Mathematics
FACTORS AND MULTIPLES MCQs
Total Questions : 40
| Page 1 of 4 pages
Answer: Option C. -> 90
:
C
First 5 multiples of 6: 6,12,18,24,30
Sum of first 5 multiples of 6 is : 6+12+18+24+30=90
:
C
First 5 multiples of 6: 6,12,18,24,30
Sum of first 5 multiples of 6 is : 6+12+18+24+30=90
Answer: Option C. -> 28
:
C
First five prime numbers are: 2, 3, 5, 7, 11
Product of first five prime numbers is 2+3+5+7+11=28
:
C
First five prime numbers are: 2, 3, 5, 7, 11
Product of first five prime numbers is 2+3+5+7+11=28
Answer: Option D. -> 4 and 6
:
D
4 and 6 form a factor pair of 24 as 4×6=24.
2 and 13 form a factor pair of 26 as 2×13=26.
1 and 13 form a factor pair of 13 as 1×13=13.
3 and 12 form a factor pair of 36 as 3×12=36.
:
D
4 and 6 form a factor pair of 24 as 4×6=24.
2 and 13 form a factor pair of 26 as 2×13=26.
1 and 13 form a factor pair of 13 as 1×13=13.
3 and 12 form a factor pair of 36 as 3×12=36.
Answer: Option D. -> Infinite
:
D
To get multiples of any number, we multiply counting numbers with that number.
Since there are infinite counting numbers, multiples of any number are also infinite.
:
D
To get multiples of any number, we multiply counting numbers with that number.
Since there are infinite counting numbers, multiples of any number are also infinite.
Answer: Option C. -> 19
:
C
HCF of two numbers × LCM of two numbers = Product of the two numbers
12×LCM=228
LCM =22812=19
:
C
HCF of two numbers × LCM of two numbers = Product of the two numbers
12×LCM=228
LCM =22812=19
Answer: Option D. -> 15 is a factor of 3
:
D
When we multiply two numbers, both the numbersare the factors of the product obtained. Here we have 3 and 5, which arethe factors of 15.
The product obtained is the multiple of the two numbers.Here we have 15, which is the muliple of both 3 and 5.
Therefore, the statement "15 is a factor of 3" is incorrect because 15 is a multiple of 3.
:
D
When we multiply two numbers, both the numbersare the factors of the product obtained. Here we have 3 and 5, which arethe factors of 15.
The product obtained is the multiple of the two numbers.Here we have 15, which is the muliple of both 3 and 5.
Therefore, the statement "15 is a factor of 3" is incorrect because 15 is a multiple of 3.
Answer: Option B. -> 4
:
B
A composite number is a number which has more than two factors.
The first few composite numbers are 4, 6, 8, 9, 10, 12, 14, 15, 16. The smallest among the set of composite numbers is 4.
:
B
A composite number is a number which has more than two factors.
The first few composite numbers are 4, 6, 8, 9, 10, 12, 14, 15, 16. The smallest among the set of composite numbers is 4.
:
Prime factorization is finding the factors of a number that are all prime.The prime factors of 15 are 3 and 5.
Answer: Option A. -> 99
:
A
The smallest factor of any number is 1 and the highest factor of any number is the number itself.
Therefore, the difference between the highest and the smallest factor of 100 is, 100−1=99
:
A
The smallest factor of any number is 1 and the highest factor of any number is the number itself.
Therefore, the difference between the highest and the smallest factor of 100 is, 100−1=99
Answer: Option B. -> 240
:
B
The least number that is exactly divisible by 15, 10 and 16is the LCM of the three numbers.
215,10,16215,5,8215,5,4215,5,2315,5,155,5,11,1,1
LCM of 15, 10 and 16=2×2×2×2×3×5=240
:
B
The least number that is exactly divisible by 15, 10 and 16is the LCM of the three numbers.
215,10,16215,5,8215,5,4215,5,2315,5,155,5,11,1,1
LCM of 15, 10 and 16=2×2×2×2×3×5=240
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