12th Grade > Physics
ELECTROMAGNETIC WAVES AND INDUCTION MCQs
Electromagnetic Waves, Electromagnetic Induction, Waves On A String
Total Questions : 73
| Page 5 of 8 pages
Answer: Option C. -> Is same for all of them
:
C
The speed of EM waves in vacuum is a constant (approx. 3×108m/s).
:
C
The speed of EM waves in vacuum is a constant (approx. 3×108m/s).
Answer: Option C. -> Beta rays
:
C
Betarays are beams of fast electrons
:
C
Betarays are beams of fast electrons
Answer: Option A. -> 0.166× 10−8 N/m2
:
A
Intensity or power per unit area of the radiations
P=fv
⇒f=Pv=0.53×108=0.166×10−8N/m2
:
A
Intensity or power per unit area of the radiations
P=fv
⇒f=Pv=0.53×108=0.166×10−8N/m2
Answer: Option D. -> 6× 10−7 m
:
D
this is the order of visible light spectrum
:
D
this is the order of visible light spectrum
Answer: Option B. -> Infrared
:
B
Infrared causes heating effect
:
B
Infrared causes heating effect
Answer: Option A. -> Polarization
:
A
Polarization is shown by only transverse waves
:
A
Polarization is shown by only transverse waves
Answer: Option A. -> Infrared photon has more energy than the photon of visible light
:
A
From the figure given below, you can clearly see that wave lengths of visible waves are lesser compared to wavelengths falling under infrared stage. Therefore, Infrared photon has less energy than the photon of visible light.
:
A
From the figure given below, you can clearly see that wave lengths of visible waves are lesser compared to wavelengths falling under infrared stage. Therefore, Infrared photon has less energy than the photon of visible light.
Answer: Option B. -> No
:
B
When a wave propagates the particles of the medium oscillate about the mean position. In the case of a wind the particles are just flowing one side. So its not a wave motion.
:
B
When a wave propagates the particles of the medium oscillate about the mean position. In the case of a wind the particles are just flowing one side. So its not a wave motion.
Answer: Option B. -> √2a
:
B
The two waves are obviously at a phase difference of π2
so the resultant amplitudeA=√a2+a2+2.a.acosπ2=√2a
:
B
The two waves are obviously at a phase difference of π2
so the resultant amplitudeA=√a2+a2+2.a.acosπ2=√2a
Answer: Option A. -> A
:
A
A1=A2
Anet=√A2+A2+2A2cos120∘
Anet=A
:
A
A1=A2
Anet=√A2+A2+2A2cos120∘
Anet=A