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12th Grade > Chemistry

ELECTROCHEMISTRY MCQs

Total Questions : 30 | Page 3 of 3 pages
Question 21. Which of the following statement(s) is(are) true?
A. The conductance of an electrolyte is dependent on the nature of the electrolyte.
B. Conductance of a solution equals the inverse of resistivity of the solution.
C. In an electrolytic cell the flow of electrons is from cathode to anode.
  1.    A, B
  2.    A,C
  3.    Only A
  4.    Only C
 Discuss Question
Answer: Option C. -> Only A
:
C
Conductance of a solution equals the inverse of resistance of the solution, and not the resistivity
In an electrolytic cell the cathode acts as the source of electrons, hence the flow of electrons is from anode to cathode.
Question 22. The specific conductance of N10 KCl solution at 20C is 0.0212 ohm1 cm1 and the resistance of cell containing this solution at 20 C is 55 ohm. The cell constant is
  1.    1.166 cm−1
  2.    2.173 cm−1
  3.    3.324 cm−1
  4.    4.616 cm−1
 Discuss Question
Answer: Option A. -> 1.166 cm−1
:
A
K=1R×cellconstant
Cell constant =K×R=0.0212×55=1.166cm1
Question 23. On passing one faraday of electricity through the electrolytic cells containing Ag+,Ni+2 and Cr+3 ions solution, the deposited Ag (At.wt.=108), Ni(At.wt.=59) and Cr(At.wt.=52) is
 Ag(in gm)Ni(in gm)Cr(in gm)a)1085952b)10829.517.3c)3619.617.3d)108108108
 
  1.    a
  2.    b
  3.    c
  4.    d
 Discuss Question
Answer: Option B. -> b
:
B
Wt. of Ag deposited = Equivalent weight of Ag =1081=108gm
Wt. of Ni deposited = Equivalent weight of Ni =592=29.5gm
Wt. of Cr deposited = Equivalent weight of Cr =523=17.3gm
Question 24. The standard electrode potentials of Zn2+Zn and Ag+Ag are 0.763 V and +0.799 V respectively. The standard potential of the cell is
  1.    1.562 V
  2.    2.361 V
  3.    −1.562 V
  4.    −2.361 V
 Discuss Question
Answer: Option A. -> 1.562 V
:
A
Ecell=EcathodeEanode=0.799(0.763)=1.562V
Question 25. Which of the following represents the anode half-cell reaction for the following galvanic cell: Cu(s)|Cu2+(aq)||Ag+(aq)|Ag(s)
  1.    Cu(s)+2Ag+(aq)→Cu2+(aq)+2Ag(s)
  2.    Cu(s)→Cu2+(aq)+2e−
  3.    2Ag+(aq)+2e−→2Ag(s)
  4.    Ag+(aq)+e−→Ag(s)
 Discuss Question
Answer: Option B. -> Cu(s)→Cu2+(aq)+2e−
:
B
Reduction reaction takes place at cathode and oxidation reaction takes place at anode.
Cathode :2Ag+(aq)+2e2Ag(s)
Anode :Cu(s)Cu2+(aq)+2e
Cell reaction :Cu(s)+2Ag+(aq)Cu2+(aq)+2Ag(s)
Question 26. The hydrogen electrode is dipped in a solution of pH=3 at 25C. The potential of the cell would be (the value of 2.303 RTFis 0.059 V
  1.    0.177 V
  2.    −0.177 V
  3.    0.087 V
  4.    0.059 V
 Discuss Question
Answer: Option B. -> −0.177 V
:
B
Reduction potential of hydrogen electrode =EH=2.303RTFlog1[H+]=0.059pH=0.059×3=0.177V
Question 27. During the electrolysis of an electrolyte, the number of ions produced is dependent on
  1.    Temperature
  2.    Nature of solvent
  3.    Nature of the electrolyte
  4.    All of the above
 Discuss Question
Answer: Option D. -> All of the above
:
D
Number of ions produced depends on degree of dissociation, which depends on factors like nature of electrolyte, nature of solvent, temperature etc.
Question 28. Which of the following conversion takes place in a galvanic cell?
  1.    Electrical energy to chemical energy
  2.    Chemical energy to electrical energy
  3.    Chemical energy to mechanical energy
  4.    Mechanical energy to chemical energy
 Discuss Question
Answer: Option B. -> Chemical energy to electrical energy
:
B
A galvanic cell is an electrochemical cell that converts the chemical energy of a spontaneous redox reaction to the electrical energy.
Question 29. What amount of current is required to be passed during a period of 5 minutes in order to deposit 0.6354gm of copper by electrolysis of aqueous cupric sulphatesolution? (Molar wt. of Copper = 63.5gm/mole)
  1.    10.24 A
  2.    6.43 A
  3.    12.68 A
  4.    1930 C
 Discuss Question
Answer: Option B. -> 6.43 A
:
B
Moles of copper to be obtained =0.635463.54=0.01 moles
Cu+++2eCu
In order to obtain 1 mole of copper , 2 Felectricity is required .
so, to obtain 0.01 moles of copper, 0.02 F of electricity will be needed.
Q=I×t=0.02F=0.02×96500C=1930C of electricity
Or, I×(5×60)=1930
I=19330=6.43A
Question 30. EAg+|Ag=0.8 volt and EZn2+|Zn=0.76 volt
Which of the following is correct?
  1.    Ag+ can be reduced by H2
  2.    Ag can oxidize H2 into H+
  3.    Zn2+ can be reduced by H2
  4.    Ag can reduce Zn2+ ion
 Discuss Question
Answer: Option A. -> Ag+ can be reduced by H2
:
A
Since H2 has greater reduction potential so it will reduceAg+.

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