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DI AND LR CLUBBED MCQs
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Question 61. In the league tournament with the conditions as described in the first question, a bookie Charlie follows the following system. In a match between two teams "a” and "b”, the team "a” wins more of their previous matches. If team "a” wins this match, he will pay Rs. 1.5 for every Re. 1 bet on team "a”. If team "b” wins this match, he will pay Rs. 2 for every Re. 1 bet on team "b”. In every match, equal money was bet on both the teams playing in that match. What was Charlie's gain, as a fraction, on the total money that he bet?
Answer: Option C. -> 14
:
C
Based on the information in the previous question, Charlie gets, say Rs 1 each from the betters of the two teams. In 6 matches, Charlie gets Rs 12. We know that the better team is winning in each case; hence his net gain is 50 paise in 6 matches ⇒ his total gain =(0.5×6)12=14
:
C
Based on the information in the previous question, Charlie gets, say Rs 1 each from the betters of the two teams. In 6 matches, Charlie gets Rs 12. We know that the better team is winning in each case; hence his net gain is 50 paise in 6 matches ⇒ his total gain =(0.5×6)12=14
:
For the minimum number of workers to complete the job in one day, the job must have been completed in the minimum possible number of man-hours in 6 days.
This is possible if the number of workers working on Day 1,2,3,4,5, and 6 are 3,2,1,2,3 and 4 respectively. Thus, the minimum number of man-hours required for the job =(3+2+1+2+3+4)×8=120.
The minimum number of workers required to complete the job in one day =(1208)=15.
:
As the pipeline AB is working at its full capacity it must be transferring 2500 litres of oil. Out of which 1200 litres is taken by B, 700 litres is taken by C, and 400 litres oil taken by E. Remaining 200 litres will go to D but D's requirement is 700 litres so AD must be carrying 500 litres.
20% of 2500 is 500. By observing the figure, the pipes where the flow is less than 500 are CE and CD i.e., 2 pipes.
:
As the pipeline AB is working at its full capacity it must be transferring 2500 litres of oil. Out of which 1200 litres is taken by B, 700 litres is taken by C, and 400 litres oil taken by E. Remaining 200 litres will go to D but D's requirement is 700 litres so AD must be carrying 500 litres.
Again from the figure, the slack in the pipeline connecting C and D is 2300 litres.
Answer: Option C. -> If both statement 1 and statement 2 are needed to answer the question and
:
C
(1) Insufficient. There is no way to find out the mean using this. Consider one set {3, 6, 9} and another {6, 9, 12}.
(2) Insufficient. Knowing that there is an odd number of terms in the set and that the median is 33 does not tell us what the mean is.
(1&2) Sufficient. In an ordered set with an odd number of terms, the median is equal to the "middle" term. Moreover, in an equally distributed set of integers (in this case, consecutive multiples of 3) the median will be equal to the mean itself.
:
C
(1) Insufficient. There is no way to find out the mean using this. Consider one set {3, 6, 9} and another {6, 9, 12}.
(2) Insufficient. Knowing that there is an odd number of terms in the set and that the median is 33 does not tell us what the mean is.
(1&2) Sufficient. In an ordered set with an odd number of terms, the median is equal to the "middle" term. Moreover, in an equally distributed set of integers (in this case, consecutive multiples of 3) the median will be equal to the mean itself.
Answer: Option C. -> B & D
:
C
Option C is the correct answer.
:
C
Option C is the correct answer.
:
Let us take the first letter of the name of each team to represent its name. Now, it is given that
(i)A + I = 12
(ii)I + SA = 11
(iii)NZ + I = 10
(iv)I + P = 8
Adding the above four equations, we get :
A + SA + 4I + NZ + P = 41 ........(1)
The total number of games played is = 4 + 3 + 2 + 1 = 10
Each game is worth two points hence total points
= 10 × 2 = 20 or A + SA + I + NZ + P = 20 .......(2)
Comparing with equation (1) and (2) we get:
3I = 21 or I = 7 (3 wins, 1 tie)
A = 5, SA = 4, NZ = 3, P=1
(2 win, 1 tie) (2 wins) (1 win, 1 tie) (1 tie)
As there are two ties they must be between A, NZ, I and P, but not SA. Now we can have
the following possibilities of ties:
Case I: I ties with A the NZ ties with P
TeamWinLoseTieA(SA/NZ),P(SAorNZ)ISA(AorNZ),P(AorNZ),I−ISA,NZ,P−ANZ(AorSA)(AorSA),IPP−A,SA,INZ
Case II: I ties with NZ,A ties with P
TeamWinLoseTieASA,NZIPSANZ,PA,I−INZ,P−NZNZPA,SAIP−I,SA,NZA
Case III: I ties with P,A ties with NZ.
TeamWinLoseTieASA,PINZSANZ,PA,I−IA,SA,NZ−PNZPSA,IAP−A,SA,NZI
Choice (c). Total number of arrangements
Case I = 2
Case II = 1
Case III = 1
--------
4
--------
Answer: Option D. -> A & C
:
D
Option D is the correct answer.
:
D
Option D is the correct answer.
Question 69. Mathew, Nathan, Olonga, Peter, Quine, Rafeal, Sutherland, Thomson and Udele are nine members in a family, who go to play to two different football clubs namely Liverpool and Chelsea. Each club can allow only three members of the same family. Peter has a priority and must be given preference by Liverpool or Chelsea. Rafeal and Nathan do not wish to go to the same club. Sutherland goes to Liverpool only and Thomson goes to Chelsea only. Olonga comes back saying that neither of the two clubs allowed him. Mathew does not go with Rafeal and Udele does not go with Quine. Nathan and Udele do not go together. If Quine, Rafeal and Sutherland go together and are allowed by one of the clubs, then who goes to play in which club, assuming that Mathew does not go to play?
Answer: Option A. -> Chelsea - Peter, Udele, Thomson or Peter, Nathan, Thomson
:
A
According to the condition that Sutherland goes to Liverpool only, Quine, Rafeal and Sutherland go to Liverpool. Thus Options (C) and (D) are not possible. Now, Peter is given preference and Thomson goes to Chelsea only thus possible answer options can be (A) and (B). Since Mathew does not play so Option (B) can be discarded. Thus option (A) is the answer.
:
A
According to the condition that Sutherland goes to Liverpool only, Quine, Rafeal and Sutherland go to Liverpool. Thus Options (C) and (D) are not possible. Now, Peter is given preference and Thomson goes to Chelsea only thus possible answer options can be (A) and (B). Since Mathew does not play so Option (B) can be discarded. Thus option (A) is the answer.
Question 70. Four people need to cross a bridge at night. They have one flashlight for the four of them, but the bridge is only wide enough for two to cross at a time. Because it's so dark, anyone crossing the bridge must do so with the flashlight. Person A can walk across in 1 minute. Person B takes 2 minutes; person C takes 5 minutes, and finally person D needs a full 10 minutes to cross. Naturally, if two people are crossing the bridge, they move with the speed of the slower person. What is the shortest amount of time it will take for all four to get to the other side?
Answer: Option A. -> 18
:
A
Total amount of time required = 10+5+2+1 = 18 min
:
A
Total amount of time required = 10+5+2+1 = 18 min
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