11th And 12th > Chemistry
COORDINATION COMPOUNDS MCQs
Total Questions : 30
| Page 1 of 3 pages
Answer: Option C. ->
Will give the tests of SO−24 ions
:
C
[Cu(NH3)4]SO4→[Cu(NH3)4]2++SO−24
It will give test for SO−24
:
C
[Cu(NH3)4]SO4→[Cu(NH3)4]2++SO−24
It will give test for SO−24
Answer: Option D. ->
None of these
:
D
Organometallics are used to make all of these.
:
D
Organometallics are used to make all of these.
Answer: Option A. ->
CaOCl2
:
A
Mixed salt contains two different types of cations or anions. It has Ca2+, it also contains two anions Cl− and OCl−.
:
A
Mixed salt contains two different types of cations or anions. It has Ca2+, it also contains two anions Cl− and OCl−.
Answer: Option C. ->
[Cu(NH3)4]2+
:
C
[Cu(NH3)4]2+ is square planar
Hybridazation state of Cu+2 is dsp2
:
C
[Cu(NH3)4]2+ is square planar
Hybridazation state of Cu+2 is dsp2
Answer: Option D. ->
Ti4+
:
D
This catalyst is made up of TiCl3+Al(C2H5)2Cl
:
D
This catalyst is made up of TiCl3+Al(C2H5)2Cl
Answer: Option B. ->
[K2NiF6]
:
B
Nickel has + 4 oxidation state.
:
B
Nickel has + 4 oxidation state.
Answer: Option C. ->
Platinum
:
C
Zeise’s salt is K[PtCl3(C2H4)]
:
C
Zeise’s salt is K[PtCl3(C2H4)]
Answer: Option C. ->
5
:
C
EAN = 36 so, 26 + 2 × n = 36
n = 5
:
C
EAN = 36 so, 26 + 2 × n = 36
n = 5
Answer: Option A. ->
6
:
A
According to Werner theory
:
A
According to Werner theory
Answer: Option B. ->
Complexes always give ions in solution.
:
B
You can have complexes that do not form ions in solution.
e.g. [Fe(CO)5]
:
B
You can have complexes that do not form ions in solution.
e.g. [Fe(CO)5]