Answer: Option C. -> CH2 = C = CH2
:
C
Molecule is non-planar

Answer: Option D. -> BF3
:
D
$B{F}_3$ is ${sp}^2$ hybridised.
$C{H}_4$, ${Cl{O}_4}^{-1}$ and ${S{O}_4}^{-2}$​​​​​​​​​​​​​​ are${sp}^3$ hybridised.

Answer: Option A. -> 16(|xA−xB|)+3.5(xA−xB)2
:
A
% ionic character = $16(|x_A-x_B|)+3.5(x_A-x_B{)}^2$
where '$x_A$ ' is the electronegativity of one element and $x_B$ is the electronegativity of the other element.
The first expression includes a modulus because we are interested in thedifference in electronegativity.
Note: This gives the % ionic character. To calculate % covalentcharacter, we have to do 1 - (% ionic character).

Answer: Option A. -> Glycerol
:
A
Glycerol - a triol,formsmore hydrogen bonds

Answer: Option C. -> C - F
:
C
$\bullet$ Electronegativity is a measure of the tendency of an atom to attract a bonding pair of electrons. The polar character depends on the electronegativity difference of the constituent atoms.
$\bullet$ Since, carbon (C) is common among all options hence, the polar character of molecules will depend on the electronegativity of other atoms.
$\bullet$ Fluorine is the most electronegative element. Hence, maximum electronegativity difference is seen in carbon and fluorine (C - F). Thus, the C-F bond has the most polar character.

Answer: Option B. -> C - C < C - H < H - H
:
B
H - H bond energy is the highest due to s-s overlapping (exceptional case)

Answer: Option C. -> C - 2 - ii
:
C
Pyramidal has three bond pair and one lone pair like $N{H}_3$

Answer: Option A. -> NH3, μ=0, Trigonal pyramidal
:
A
$N{H}_3$ has dipole moment of 1.48D

Answer: Option D. -> F - H ........F 
:
D
F is most electronegative atom

Answer: Option D. -> 12.5%
:
D
% of ionic character = dipole moment(observed)/ calculated value $\times$ 100
Calculated dipole moment = charge $\times$ distance, charge as you know is $1.6\times {10}^{-19}$ C