Quantitative Aptitude
BOATS AND STREAMS MCQs
Total Questions : 948
| Page 91 of 95 pages
Answer: Option D. -> Any two of the three
Answer: Option D. -> Both I and II are necessary to answer
Answer: Option D. -> 80 km
LET THE DISTANCE BETWEEN THE TWO PARTS BE X KM.
THEN SPEED DOWNSTREAM = X/4 KM/HR.
SPEED UPSTREAM = X/5 KM/HR
SPEED OF THE STREAM = ½ (X/4 –X/5)
THEREFORE, ½(X/4 –X/5) = 2. => X/4 –X/5 = 4 => X = 80.
HENCE, THE DISTANCE BETWEEN THE TWO PORTS IS 80KM.
LET THE DISTANCE BETWEEN THE TWO PARTS BE X KM.
THEN SPEED DOWNSTREAM = X/4 KM/HR.
SPEED UPSTREAM = X/5 KM/HR
SPEED OF THE STREAM = ½ (X/4 –X/5)
THEREFORE, ½(X/4 –X/5) = 2. => X/4 –X/5 = 4 => X = 80.
HENCE, THE DISTANCE BETWEEN THE TWO PORTS IS 80KM.
Answer: Option C. -> 6 hours 50 min
LET THE SPEED OF MOTOR BOAT BE 36X KM/HR AND THAT OF CURRENT OF WATER BE 5X KM/HR
SPEED DOWNSTREAM = (36X +5X)KM/HR = 41X KM/HR
SPEED UPSTREAM = (36 -5X)KM/HR = 31X KM/HR
DISTANCE COVERED DOWNSTREAM = (41X × 31/6)KM
DISTANCE UPSTREAM = [1271X/6 × 1/31X]HRS
= 41/6 HRS = 6HRS 50 MIN
LET THE SPEED OF MOTOR BOAT BE 36X KM/HR AND THAT OF CURRENT OF WATER BE 5X KM/HR
SPEED DOWNSTREAM = (36X +5X)KM/HR = 41X KM/HR
SPEED UPSTREAM = (36 -5X)KM/HR = 31X KM/HR
DISTANCE COVERED DOWNSTREAM = (41X × 31/6)KM
DISTANCE UPSTREAM = [1271X/6 × 1/31X]HRS
= 41/6 HRS = 6HRS 50 MIN
Answer: Option E. -> None of these
SPEED DOWNSTREAM = (30 X 2/5)KM/HR = 12KM/HR
SPEED UPSTREAM = (30 X 4/15) KM/HR = 8 KM/HR
SPEED OF BOAT IN STILL WATER = ½ (12 + 8)KM/HR = 10 KM/HR
SPEED DOWNSTREAM = (30 X 2/5)KM/HR = 12KM/HR
SPEED UPSTREAM = (30 X 4/15) KM/HR = 8 KM/HR
SPEED OF BOAT IN STILL WATER = ½ (12 + 8)KM/HR = 10 KM/HR
Answer: Option E. -> None of these
SPEED DOWNSTREAM = 24/10 KM/HR = 2.4 KM/HR
SPEED UPSTREAM = 24/12 KM/HR = 2 KM/HR
SPEED OF THE BOAT IN STILL WATER = ½ (2.4 +2)KM/HR = 2.2 KM/HR
SPEED DOWNSTREAM = 24/10 KM/HR = 2.4 KM/HR
SPEED UPSTREAM = 24/12 KM/HR = 2 KM/HR
SPEED OF THE BOAT IN STILL WATER = ½ (2.4 +2)KM/HR = 2.2 KM/HR
Answer: Option A. -> 5km/hr
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
Answer: Option E. -> None of these
LET THE DISTANCE BETWEEN A AND B BE X KM.
TOTAL TIME = X/(9 + 1) + X/(9 – 1) = 4.5
=> X/10 + X/8 = 9/2 => (4X + 5X)/40 = 9/2 => X = 20 KM.
LET THE DISTANCE BETWEEN A AND B BE X KM.
TOTAL TIME = X/(9 + 1) + X/(9 – 1) = 4.5
=> X/10 + X/8 = 9/2 => (4X + 5X)/40 = 9/2 => X = 20 KM.
Answer: Option D. -> 14, 4
LET THE SPEED OF THE MAN IN STILL WATER AND SPEED OF STREAM BE X KMPH AND Y KMPH RESPECTIVELY.
GIVEN X + Y = 18 — (1)
AND X – Y = 10 — (2)
FROM (1) & (2) 2X = 28 => X = 14, Y = 4.
LET THE SPEED OF THE MAN IN STILL WATER AND SPEED OF STREAM BE X KMPH AND Y KMPH RESPECTIVELY.
GIVEN X + Y = 18 — (1)
AND X – Y = 10 — (2)
FROM (1) & (2) 2X = 28 => X = 14, Y = 4.
Answer: Option D. -> 12 seconds
SPEED OF THE BOAT DOWNSTREAM = 15 + 3 = 18 KMPH
= 18 * 5/18 = 5 M/S
HENCE TIME TAKEN TO COVER 60 M = 60/5 = 12 SECONDS.
SPEED OF THE BOAT DOWNSTREAM = 15 + 3 = 18 KMPH
= 18 * 5/18 = 5 M/S
HENCE TIME TAKEN TO COVER 60 M = 60/5 = 12 SECONDS.