11th And 12th > Chemistry
BIOMOLECULES MCQs
Total Questions : 30
| Page 1 of 3 pages
Answer: Option B. ->
Carbohydrate
:
B
(b)
Molisch's test is done for the detection of carbohydrate bond formation.
:
B
(b)
Molisch's test is done for the detection of carbohydrate bond formation.
Answer: Option C. ->
Both
:
C
Option (c)
A substance tht forms Zwitter ion can have functional groups −NH2COOH and −NH2−NH2−SO3H
:
C
Option (c)
A substance tht forms Zwitter ion can have functional groups −NH2COOH and −NH2−NH2−SO3H
Answer: Option C. ->
Cysteine
:
C
Option (c)
You can clearly see that cysteine is the only amino acid from the options given which contains a sulphur in its structure. You can remember this by going back to the video of the secondary structure of proteins where we talka about the Disulphide linkages which gives shape to the protein sheets.
:
C
Option (c)
You can clearly see that cysteine is the only amino acid from the options given which contains a sulphur in its structure. You can remember this by going back to the video of the secondary structure of proteins where we talka about the Disulphide linkages which gives shape to the protein sheets.
Answer: Option D. ->
Glucose and fructose
:
D
Option (d)
C12H22O11Canesugar+H2O→C6H12O6Glucose+C6H12O6Fructose
:
D
Option (d)
C12H22O11Canesugar+H2O→C6H12O6Glucose+C6H12O6Fructose
Answer: Option A. ->
Glucose
:
A
Option (a)
Starch is a condensation polymer made up of hundreds of glucose monomers
:
A
Option (a)
Starch is a condensation polymer made up of hundreds of glucose monomers
Answer: Option A. ->
Cellulose
:
A
We cannot digest cellulose, which is a polysaccharide. Our digestive system is not capable of digesting this tough carbohydrate. However, herbivorous animals like cows are well-equipped to do just that.
:
A
We cannot digest cellulose, which is a polysaccharide. Our digestive system is not capable of digesting this tough carbohydrate. However, herbivorous animals like cows are well-equipped to do just that.
Answer: Option B. ->
Configuration
:
B
Option (b)
It is clear from the above picture that there is no other difference in these 2 structures other than the difference at the C-1 carbon, which can be attributed to the difference in the configuration of the carbon. This carbon is referred to as the anomeric carbon to highlight this important feature.
:
B
Option (b)
It is clear from the above picture that there is no other difference in these 2 structures other than the difference at the C-1 carbon, which can be attributed to the difference in the configuration of the carbon. This carbon is referred to as the anomeric carbon to highlight this important feature.
Answer: Option B. ->
Red
:
B
Option (b)
Glucose + Fehling solution ® Gluconic acid + Cu2O(Redppt)
:
B
Option (b)
Glucose + Fehling solution ® Gluconic acid + Cu2O(Redppt)
Answer: Option B. ->
Fructose
:
B
Option (b)
Sugar Relative sweetness order-
Sucrose 100
Glucose 74
Lactose 16
Fructose 173
From this, it is clear that Fructose is the sweetest.
You might have guessed it's either Sucrose and Fructose from experience, but between these 2 we will need some proper experimental techniques to determine which is the sweeter one.
:
B
Option (b)
Sugar Relative sweetness order-
Sucrose 100
Glucose 74
Lactose 16
Fructose 173
From this, it is clear that Fructose is the sweetest.
You might have guessed it's either Sucrose and Fructose from experience, but between these 2 we will need some proper experimental techniques to determine which is the sweeter one.
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