7th Grade > Mathematics
ALGEBRAIC EXPRESSIONS MCQs
Total Questions : 116
| Page 2 of 12 pages
Answer: Option A. -> True
:
A
In the expression "x”, the variable is x and it does not have any constant term.
For example, in the expression 5 + 10y, the constant term is 5.
Hence, the statement is correct.
:
A
In the expression "x”, the variable is x and it does not have any constant term.
For example, in the expression 5 + 10y, the constant term is 5.
Hence, the statement is correct.
Answer: Option B. -> False
:
B
A polynomial with two unlike terms is called a binomial and the one with three unlike terms is called a trinomial.
Hence, 25x2+5+15is a trinomial.
:
B
A polynomial with two unlike terms is called a binomial and the one with three unlike terms is called a trinomial.
Hence, 25x2+5+15is a trinomial.
Answer: Option A. -> 9x2+9y+5z2+10p
:
A
Given expression is
2x2+3y+5z2 +10p+6y+7x2
Group the like terms:
= (2x2+7x2) + (3y+6y) + 10p + 5z2
Solve groups:
=x2(2+7)+y(3+6)+5z2+10p
=9x2+9y+5z2+10p
:
A
Given expression is
2x2+3y+5z2 +10p+6y+7x2
Group the like terms:
= (2x2+7x2) + (3y+6y) + 10p + 5z2
Solve groups:
=x2(2+7)+y(3+6)+5z2+10p
=9x2+9y+5z2+10p
:
Coefficient is defined as anumber or symbol multiplied to a variable or an unknown quantity in an algebraic term.The coefficient of x in '2x + 5y' is 2.
:
Coefficient is defined as anumber or symbol multiplied to a variable or an unknown quantity in an algebraic term.
The coefficient of the term x5in expression x3−x5is -1,
−x5 = −1×(x5)
∴ The coefficient ofx5 is equal to -1.
:
Steps: 1 Mark
Final expression: 1 Mark
Value: 1 Mark
(0.4p−0.5q)2
=(0.4p−0.5q)×(0.4p−0.5q)
=(0.4p)×(0.4p)−(0.4p×0.5q+0.4p×0.5q)+(0.5q)×(0.5q)
=0.16p2−0.40pq+0.25q2
Given that
p = 5 and q = 4
on substituting the values we get,
=0.16×52−0.40×5×4+0.25×42
=4−8+4
=0
:
Answer: 1 Mark
Steps: 1 Mark
Type: 1 Mark
According to question,
(3a−b+3c)−[(a+b+c)+(2a−b+2c)]
=(3a−b+3c)−[(a+b+c+2a−b+2c)]
=(3a−b+3c)−(3a+3c)
=(3a−b+3c−3a−3c)
=−b
The given expression contains only −b, So it is a monomial.
:
Answer: 1 Mark
Reason: 1 Mark
The statement is incorrect.
Acoefficient is defined as anumber or symbol multiplied to a variable or an unknown quantity in an algebraic term.
It is only defined for the terms containing variable and notfor constants.
In the expression, 4 is a constant and therefore cannot have a coefficient.
Hence, the statement is incorrect.
:
Forming the equation: 1 Mark
Steps: 2 Marks
Answer: 1 Mark
While adding or subtracting algebraic expressions we need to be aware that we can add/subtract only like terms.
Like terms have the same algebraic factors.
According to question,
⌊(4+3x)+(5−4x+2x2)⌋−⌊(3x2−5x)+(−x2+2x+5)⌋
=[4+3x+5−4x+2x2]−[3x2−5x−x2+2x+5]
=[2x2+3x−4x+5+4]−[3x2−x2+2x−5x+5]
=[2x2−x+9]−[2x2−3x+5]
=2x2−x+9−2x2+3x−5
=2x2−2x2−x+3x+9−5
=2x+4
So, the required expression is2x+4.
:
Each option: 1.5 Marks
a) Let q be the expression to be subtracted.
Then according to the question,
3x2−4y2+5xy+20−q=−x2−y2+6xy+20
⇒q=3x2−4y2+5xy+20−(−x2−y2+6xy+20)
⇒q=3x2−4y2+5xy+20+x2+y2−6xy−20
⇒q=3x2+x2−4y2+y2+5xy−6xy+20−20
⇒q=4x2−3y2−xy+0
Hence, 4x2−3y2−xy should be subtractedfrom 3x2−4y2+5xy+20 to obtain −x2−y2+6xy+20.
b) As per the question:
x2+2xy+y2 is multiplied by xy
So,xy× x2+2xy+y2
=xy×x2+xy×2xy+xy×y2
=x2+1y+2x1+1y1+1+xy1+2
∵am×an=am+n
=x3y+2x2y2+xy3