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7th Grade > Mathematics

ALGEBRAIC EXPRESSIONS MCQs

Total Questions : 116 | Page 2 of 12 pages
Question 11. The algebraic expression "x” does not contain any constant term.
  1.    True
  2.    False
 Discuss Question
Answer: Option A. -> True
:
A
In the expression "x”, the variable is x and it does not have any constant term.
For example, in the expression 5 + 10y, the constant term is 5.
Hence, the statement is correct.
Question 12. 25x2+5+15  is a binomial.
  1.    True
  2.    False
 Discuss Question
Answer: Option B. -> False
:
B
A polynomial with two unlike terms is called a binomial and the one with three unlike terms is called a trinomial.
Hence, 25x2+5+15
is a trinomial.
Question 13. The given expression '2x2+3y+5z2+10p+6y+7x2', on simplification gives:
  1.    9x2+9y+5z2+10p
  2.    11x2+2y+10z2+10p
  3.    9x2+12y+5z2+10p
  4.    19x2+10y+5z2+10p
 Discuss Question
Answer: Option A. -> 9x2+9y+5z2+10p
:
A
Given expression is
2x
2+3y+5z2 +10p+6y+7x2
Group the like terms:
= (2x2+7x2) + (3y+6y) + 10p + 5z2
Solve groups:
=
x2(2+7)+y(3+6)+5z2+10p
=9x2+9y+5z2+10p
Question 14. The coefficient of  x in '2x +5y' is __ 
 Discuss Question

:
Coefficient is defined as anumber or symbol multiplied to a variable or an unknown quantity in an algebraic term.The coefficient of x in '2x + 5y' is 2.
Question 15. The coefficient of term x5 in the expression x3x5 is
___
 Discuss Question

:
Coefficient is defined as anumber or symbol multiplied to a variable or an unknown quantity in an algebraic term.
The coefficient of the term x5in expression x3x5is -1,
x5 = 1×(x5)
The coefficient ofx5 is equal to -1.
Question 16. Find  (0.4p0.5q)2. If p = 5 and q = 4, evaluate the value of the expression. [3 MARKS]
 Discuss Question

:
Steps: 1 Mark
Final expression: 1 Mark
Value: 1 Mark
(0.4p0.5q)2
=(0.4p0.5q)×(0.4p0.5q)
=(0.4p)×(0.4p)(0.4p×0.5q+0.4p×0.5q)+(0.5q)×(0.5q)
=0.16p20.40pq+0.25q2
Given that
p = 5 and q = 4
on substituting the values we get,
=0.16×520.40×5×4+0.25×42
=48+4
=0
Question 17. Subtract the sum of (a+b+c) and (2ab+2c) from 3ab+3c. Name the type of expression formed. [3 MARKS]
 Discuss Question

:
Answer: 1 Mark
Steps: 1 Mark
Type: 1 Mark
According to question,
(3ab+3c)[(a+b+c)+(2ab+2c)]
=(3ab+3c)[(a+b+c+2ab+2c)]
=(3ab+3c)(3a+3c)
=(3ab+3c3a3c)
=b
The given expression contains only b, So it is a monomial.
Question 18. Is the statement given below correct? Explain.  
"In the expression x + 4y + 4, the coefficient of x is 1, y is 4 and of 4 is 1".  [2 MARKS]
 Discuss Question

:
Answer: 1 Mark
Reason: 1 Mark
The statement is incorrect.

Acoefficient is defined as anumber or symbol multiplied to a variable or an unknown quantity in an algebraic term.
It is only defined for the terms containing variable and notfor constants.
In the expression, 4 is a constant and therefore cannot have a coefficient.
Hence, the statement is incorrect.
Question 19. From the sum of
4+3x and 54x+2x2,
subtract the sum of
3x25x and x2+2x+5.  [4 MARKS]
 Discuss Question

:
Forming the equation: 1 Mark
Steps: 2 Marks
Answer: 1 Mark
While adding or subtracting algebraic expressions we need to be aware that we can add/subtract only like terms.
Like terms have the same algebraic factors.
According to question,
(4+3x)+(54x+2x2)(3x25x)+(x2+2x+5)
=[4+3x+54x+2x2][3x25xx2+2x+5]
=[2x2+3x4x+5+4][3x2x2+2x5x+5]
=[2x2x+9][2x23x+5]
=2x2x+92x2+3x5
=2x22x2x+3x+95
=2x+4
So, the required expression is2x+4.
Question 20. A) What should be subtracted from 3x24y2+5xy+20 to obtain x2y2+6xy+20?
b) Find the final expression when the algebraic expression x2+2xy+y2 is multiplied by xy. [4 MARKS]
 Discuss Question

:
Each option: 1.5 Marks
a) Let q be the expression to be subtracted.
Then according to the question,
3x24y2+5xy+20q=x2y2+6xy+20
q=3x24y2+5xy+20(x2y2+6xy+20)
q=3x24y2+5xy+20+x2+y26xy20
q=3x2+x24y2+y2+5xy6xy+2020
q=4x23y2xy+0
Hence, 4x23y2xy should be subtractedfrom 3x24y2+5xy+20 to obtain x2y2+6xy+20.
b) As per the question:
x2+2xy+y2 is multiplied by xy
So,xy× x2+2xy+y2
=xy×x2+xy×2xy+xy×y2
=x2+1y+2x1+1y1+1+xy1+2
am×an=am+n
=x3y+2x2y2+xy3

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