Question
Subtract the sum of (a+b+c) and (2a−b+2c) from 3a−b+3c. Name the type of expression formed. [3 MARKS]
Answer:
:
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According to question,
(3a−b+3c)−[(a+b+c)+(2a−b+2c)]
=(3a−b+3c)−[(a+b+c+2a−b+2c)]
=(3a−b+3c)−(3a+3c)
=(3a−b+3c−3a−3c)
=−b
The given expression contains only −b, So it is a monomial.
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:
Answer: 1 Mark
Steps: 1 Mark
Type: 1 Mark
According to question,
(3a−b+3c)−[(a+b+c)+(2a−b+2c)]
=(3a−b+3c)−[(a+b+c+2a−b+2c)]
=(3a−b+3c)−(3a+3c)
=(3a−b+3c−3a−3c)
=−b
The given expression contains only −b, So it is a monomial.
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