7th Grade > Mathematics
ALGEBRAIC EXPRESSIONS MCQs
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A
When a variable 'x' is multiplied with another variable 'y', the algebraic expression formed is 'xy'.
:
−2(3y+6)=(−2×3y)+(−2×6)
=−6y+(−12)
=−6y−12
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Steps: 1 Mark
Answer: 1 Mark
The value of the polynomial a3+3a2b+2ab−b2 at a = -2 and b = 3
a3+3a2b+2ab−b2
On substituting the values of a and b in the above expression we get:
=(−2)3+3×(−2)2×3+2×(−2)×3−32
=−8+36−12−9=7
So, the value of the polynomial a3+3a2b+2ab−b2 at a=−2 and b=3 is 7.
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Numerical Coefficients: 1 Mark
Sum: 1 Mark
The numerical coefficient of 4x2 = 4
The numerical coefficient of 12xy = 12
The numerical coefficient of −5y2 = -5
The numerical coefficient of −11y = -11
Sum of the coefficients = 4 + 12 - 5 - 11 = 0
Hence, the sum of all the numerical coefficients in the above expression is zero.
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Simplified equation: 1 Mark
Name of expression: 1 Mark
The given equation is:
(3x−8y+4)−(x−y)
=3x−8y+4−x+y
=2x−7y+4
where 2x, 7y and 4 are the three terms.
So, the simplified equation is a trinomial.
:
Each part: 1.5 Marks
(i) Value of the expression for x=−4
2x2+12x+3
2(−4)2+12(−4)+3
2(16)−48+3
32−48+3=−15
Hence, the value of expression 2x2+12x+3 at x=−4 is lesser than 15.
(ii) As per question
x2 is added to 2x2+12x+3 and 15 is subtracted from it
So, the final expression is:
2x2+12x+3+x2−15
3x2+12x−12
On putting x = -4 in the above equation we get:
3×(−4)2+12×(−4)−12
=48−48−12
=−12
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Forming the expression: 1 Mark
Value of expression: 1 Mark
The product of two numbers, m, and n is
m×n.
Three times the product is 3mn.
Adding 5 to three times the product
= 5 + 3mn
The expression formed is 5 + 3mn
The value of the product at m = 4 and n = 5
=5+3×4×5=65
Hence, the value of the expression if m = 4 and n = 5 is 65.
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Formula: 1 Mark
Steps: 1 Mark
Answer: 1 Mark
Given that:
Two adjacent sides of a rectangle are 5x2−3y2 and x2−2xy.
The perimeter of a rectangle is given by:
Perimeter of a rectangle = 2 (Length + Breadth)
=2[(5x2−3y2)+(x2−2xy)]
=[10x2−6y2)+(2x2−4xy)]
=12x2−6y2−4xy
So, the perimeter of the rectangle is 12x2−6y2−4xy.
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Steps: 2 Marks
Answer: 1 Mark
Steps to be followed to decide whether the given terms are like or not are as followed:
i) Ignore the numerical coefficients.
ii) Check the variables in the terms. They must be same otherwise they are unlike terms.
iii) Next, check the powers of each variable in the terms. They should be the same and if they are not then they are not like terms.
We have to check if x2 and xy are like terms.
The variables in both these expressions are x and y.
The power of y is equal in both the expressions.
But the power of x in the term x2y is 2, while in the term xy it is one.
∴ The terms are not like.
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Forming the equation: 1 Mark
Steps: 1 Mark
Result: 1 Mark
According to question,
= (3x - y + 11) + (- y - 11) - (3x - y - 11)
= 3x - y + 11 - y - 11 - 3x + y + 11
= 3x - 3x - y - y + y + 11 - 11 + 11
= (3 - 3)x - (1 + 1 - 1)y + 11 + 11 -11
= 0x - y + 11
= -y +11
The required expression is -y +11.