6th Grade > Mathematics
ALGEBRA MCQs
Total Questions : 96
| Page 2 of 10 pages
Answer: Option B. -> 2x + 5
:
B
Given Ram's age isx.
Twice of Ram's age is 2x.
∴ 5 more than twice Ram's age is 2x+5 which gives Raju's age.
:
B
Given Ram's age isx.
Twice of Ram's age is 2x.
∴ 5 more than twice Ram's age is 2x+5 which gives Raju's age.
:
Each option: 1 Mark
(i) p+q+3r,whenp=1,q=5,r=2
p+q+3r=1+5+3(2)=12
(ii) 2a+4b+5c,whena=5,b=10,c=20
2a+4b+5c=2(5)+4(10)+5(20)
=10+40+100=150
(iii) 3a−2b,whena=8,b=10
3a−2b=3(8)−2(10)
=24−20=4
(iv) 5x+3y−6z,whenx=3,y=5,z=4
5x+3y−6z=5(3)+3(5)−6(4)=15+15−24
=30−24=6
Answer: Option D. -> 6
:
D
Since 4xy2and 2xy2are like terms, the given expression can be written as follows.
4xy2+x3−x5+2xy2=6xy2+x3−x5
Therefore, thecoefficient of xy2is 6.
:
D
Since 4xy2and 2xy2are like terms, the given expression can be written as follows.
4xy2+x3−x5+2xy2=6xy2+x3−x5
Therefore, thecoefficient of xy2is 6.
Answer: Option C. -> Temperature of a place in a day at different times
:
C
The temperature of a place in a day at different times will be different. So it is a variable.
The number of days in a week and the number of months in a year always remain the same. So these are constants.
5 has a fixed value. So it is a constant.
:
C
The temperature of a place in a day at different times will be different. So it is a variable.
The number of days in a week and the number of months in a year always remain the same. So these are constants.
5 has a fixed value. So it is a constant.
Answer: Option C. -> 7
:
C
Let the number be x.
Therefore, the successor of number is x + 1 and the predecessor is x - 1.
Given that thesum of successor and predecessor is 14.
∴x+1+x−1=14⇒2x=14⇒x=142⇒x=7
So, the number should be 7.
:
C
Let the number be x.
Therefore, the successor of number is x + 1 and the predecessor is x - 1.
Given that thesum of successor and predecessor is 14.
∴x+1+x−1=14⇒2x=14⇒x=142⇒x=7
So, the number should be 7.
Answer: Option A. -> 0
:
A
2xy=2×x×y
On substituting the values of x and y, we get
2xy=2×4×0=8×0=0
:
A
2xy=2×x×y
On substituting the values of x and y, we get
2xy=2×4×0=8×0=0
:
Variable is the unknown quantity which can have different values at different instances and they are usually represented by alphabets. In above expression, x is the variable.
Answer: Option D. -> 34 units
:
D
When y=5
Distance=(2y2+y+2)=2×52+5+2=50+5+2=57 units
When y =3,
Distance =(2y2+y+2)=2×32+3+2=18+3+2=23 units
∴ Required difference = 57 – 23 = 34 units.
:
D
When y=5
Distance=(2y2+y+2)=2×52+5+2=50+5+2=57 units
When y =3,
Distance =(2y2+y+2)=2×32+3+2=18+3+2=23 units
∴ Required difference = 57 – 23 = 34 units.
Answer: Option B. -> ₹ (13x - 1)
:
B
Total distance travelled = xkm
So, the distance applicable for additional charge is(x−2)km.
∴ Total additional charge =₹13(x−2)
Total charge = Fixed charge + Additional charge
=13(x−2)+25
=13x−26+25
=₹(13x -1)
∴ Expression for total charge is ₹(13x -1).
:
B
Total distance travelled = xkm
So, the distance applicable for additional charge is(x−2)km.
∴ Total additional charge =₹13(x−2)
Total charge = Fixed charge + Additional charge
=13(x−2)+25
=13x−26+25
=₹(13x -1)
∴ Expression for total charge is ₹(13x -1).
Answer: Option D. -> Polynomial
:
D
35xy, 45x, 5y2 and 25xyz are unlike terms.
Therefore, there are 4 unlike terms. So it is a polynomial.
:
D
35xy, 45x, 5y2 and 25xyz are unlike terms.
Therefore, there are 4 unlike terms. So it is a polynomial.