6th Grade > Mathematics
ALGEBRA MCQs
:
Each Option: 1 Mark
(i) 4x+5=25
⇒4x=25−5
⇒4x=20
Divide by 4 on both sides,
4x÷4=20÷4
x=5
(ii) x−213=512
⇒x−73=112(Taking LCM of 1 and 3 )
⇒3x−73=112
⇒3x=112×3+7
⇒3x=33+142=472
⇒x=476=756=7.833
(iii) (7x+8)÷7=8
⇒7x+87=8
⇒7x=8×7−8=56−8=48
⇒x=487=667=6.86
:
Each option: 1 Mark
(i) x2x2=12x=12(2)=14
(ii) xzyz=xy=25
(iii) zx=42=16
(iv) yx=52=25
:
6th: 1 Mark
4th: 1 Mark
Answer: 1 Mark
Given that, nth term is 2n2+5
Therefore,
6thterm=2×62+5
=2×36+5=77
4thterm=2×42+5
=2×16+5=32+5=37
Difference=77–37=40.
:
Each option: 1 Mark
(a) Let the number be x
Twice of number =2x
According to question, 2x−13=3
(b) Let the number be x
One-fifth of number =x5
According to question,x5=x−5
(c) Let the number be x
Two-third of number =2x3
According to question, 2x3=12
(d) Let the number be x
Twice a number =2x
According to question, 2x+9=13
:
A's Income: 1 Mark
B's Income: 1 Mark
C's Income: 1 Mark
Steps: 1 Mark
Let the income of C = ₹ x
Income of B = ₹ 3x
Income of A = twice of income of B = 2(₹ 3x) = ₹ 6x
Sum of their income
⇒10x=72000⇒x=₹ 7200
Income of C
= ₹ x = ₹ 7200
Income of A
=₹ 6x=₹ 6×7200=₹ 43200
Income of B
=₹ 3x=₹ 3×7200=₹ 21600
(i) Given that a printer prints 5 pages less in the second minute to what it prints in the first minute. Given that it prints 77 pages in two minutes, how many pages does it print in the first minute?
(ii) The length of a rectangle is 4 metres less than three times the breadth of the rectangle. Express the breadth in terms of length. [4 MARKS]
:
Each option: 2 Marks
(i) Let the number of pages printed in first minute =x
Number of pages printed in the second minute =x−5
Total number of pages printed in the first two minutes =x+x−5
⇒2x−5=77
⇒2x=77+5
⇒2x=82
⇒x=41
(ii) Let L and B be length and breadth of the rectangle respectively
Given L = 3B - 4
Adding 4 to both sides
L+4 =3B -4 + 4
L + 4 = 3B
Dividing both sides by 3, we get,
B=L+43