6th Grade > Mathematics
ALGEBRA MCQs
Total Questions : 96
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Answer: Option C. -> 14
:
C
x−23=2x7⇒7×(x−2)=3×2x⇒7x−14=6x⇒7x−6x=14⇒x=14
:
C
x−23=2x7⇒7×(x−2)=3×2x⇒7x−14=6x⇒7x−6x=14⇒x=14
Answer: Option A. -> −403
:
A
2x+10=8x⇒2x=8×(x+10)⇒x=4×(x+10)⇒x=4x+40⇒−40=4x−x⇒−40=3x⇒x=−403
:
A
2x+10=8x⇒2x=8×(x+10)⇒x=4×(x+10)⇒x=4x+40⇒−40=4x−x⇒−40=3x⇒x=−403
Answer: Option D. -> x+5=15
:
D
Let us take the number to be x.
When 5 is added to the number, we get x+5.
Now, we know that when 5 is added to that number, we get 15.
Hence, x+5=15.
:
D
Let us take the number to be x.
When 5 is added to the number, we get x+5.
Now, we know that when 5 is added to that number, we get 15.
Hence, x+5=15.
Answer: Option C. -> 22
:
C
Let the number be x.
∴2x−41=3⇒2x=44⇒x=442=22
:
C
Let the number be x.
∴2x−41=3⇒2x=44⇒x=442=22
Answer: Option D. -> 37 years old
:
D
Rahul's dad's age is 4 more than 3 times of his age.
Let Rahul's present age be x years.
Then his dad's age = (3x + 4) years.
Given that Rahul's present age is 11, x = 11.
Hence, his dad's present age = (3 × 11) + 4 = 37 years.
:
D
Rahul's dad's age is 4 more than 3 times of his age.
Let Rahul's present age be x years.
Then his dad's age = (3x + 4) years.
Given that Rahul's present age is 11, x = 11.
Hence, his dad's present age = (3 × 11) + 4 = 37 years.
:
Solution: 1 Mark
The algebraic form of the given statement is 2x+28=45
:
A's Income: 1 Mark
B's Income: 1 Mark
C's Income: 1 Mark
Steps: 1 Mark
Let the income of C = ₹ x
Income of B = ₹ 3x
Income of A = twice of income of B = 2(₹3x) = ₹6x
Sum of their income
⇒10x=72000⇒x=₹7200
Income of C
=₹ x = ₹ 7200
Income of A
=₹6x=₹6×7200=₹43200
Income of B
=₹3x=₹3×7200=₹21600
:
Solution: 1 Mark each
(i) (4a−b+6c)−(3a−4b+5c)
= 4a−b+6c−3a+4b−5c
= 4a−3a−b+4b+6c−5c
= a+3b+c
(ii) (a−4b−2c)−(5a−3b+2c)
= a−4b−2c−5a+3b−2c
= a−5a−4b+3b−2c−2c
= −4a−b−4c
:
Equation: 1 Mark
Steps: 1 Mark
Answer: 1 Mark
Let the number be x.
The number decreased by 15 ⇒(x−15)
The number so obtained is multip[lied by 3⇒3×(x−15)
Given: 3(x−15)=81⇒3x−45=81
⇒3x=81+45
⇒x=1263=42
∴ The required number = 42
Answer: Option A. -> True
:
A
In order to check whether the above equation 5t-4 =1 is satisfied for t =1, we simply put 1 in place of t, So substituting t = 1 in the equation , we get
LHS = 5× (1)- 4 =1 andRHS = 1.
Since, LHS=RHS,t =1 satisfies the equation 5t-4 =1.
:
A
In order to check whether the above equation 5t-4 =1 is satisfied for t =1, we simply put 1 in place of t, So substituting t = 1 in the equation , we get
LHS = 5× (1)- 4 =1 andRHS = 1.
Since, LHS=RHS,t =1 satisfies the equation 5t-4 =1.