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6th Grade > Mathematics

ALGEBRA MCQs

Total Questions : 96 | Page 1 of 10 pages
Question 1. Solve for x:x23=2x7
  1.    7
  2.    -14
  3.    14
  4.    -7
 Discuss Question
Answer: Option C. -> 14
:
C
x23=2x77×(x2)=3×2x7x14=6x7x6x=14x=14
Question 2. If 2x+10=8x, then the value of x is 
  1.    −403
  2.    3
  3.    -40
  4.    403
 Discuss Question
Answer: Option A. -> −403
:
A
2x+10=8x2x=8×(x+10)x=4×(x+10)x=4x+4040=4xx40=3xx=403
Question 3. When 5 is added to a number, we get 15. How do we represent this in the form of an equation in variable x ?
  1.    x=15+5
  2.    x−5=15
  3.    x+15=5
  4.    x+5=15
 Discuss Question
Answer: Option D. -> x+5=15
:
D
Let us take the number to be x.
When 5 is added to the number, we get x+5.
Now, we know that when 5 is added to that number, we get 15.
Hence, x+5=15.
Question 4. A number when multiplied by 2 and decreased by 41 gives 3. Find the number.
  1.    18
  2.    20
  3.    22
  4.    24
 Discuss Question
Answer: Option C. -> 22
:
C
Let the number be x.
2x41=32x=44x=442=22
Question 5. Rahul's dad's age is 4 more than 3 times of his present age. If Rahul is 11 years old, then his dad is _____.
  1.    35 years old
  2.    36 years old
  3.    34 years old
  4.    37 years old
 Discuss Question
Answer: Option D. -> 37 years old
:
D
Rahul's dad's age is 4 more than 3 times of his age.
Let Rahul's present age be x years.
Then his dad's age = (3x + 4) years.
Given that Rahul's present age is 11, x = 11.
Hence, his dad's present age = (3 × 11) + 4 = 37 years.
Question 6. Write the given statement in algebraic form "28 more than twice of x is equal to 45." [1 MARK]
 Discuss Question

:
Solution: 1 Mark
The algebraic form of the given statement is 2x+28=45
Question 7. The income of a man A is twice the income of B. The income of B is thrice of that of C. Given that the sum of income of A, B and C is ₹72000, find the income of A, B and C? [4 MARKS]
 Discuss Question

:
A's Income: 1 Mark
B's Income: 1 Mark
C's Income: 1 Mark
Steps: 1 Mark
Let the income of C = ₹ x

Income of B = ₹ 3x
Income of A = twice of income of B = 2(₹3x) = ₹6x
Sum of their income
10x=72000x=7200
Income of C
=₹ x = ₹ 7200

Income of A
=6x=6×7200=43200
Income of B
=3x=3×7200=21600
Question 8. Subtract: [2 MARKS]
(i) 3a4b+5c from 4ab+6c
(ii) 5a3b+2c from a4b2c
 Discuss Question

:
Solution: 1 Mark each
(i) (4ab+6c)(3a4b+5c)
= 4ab+6c3a+4b5c
= 4a3ab+4b+6c5c
= a+3b+c
(ii) (a4b2c)(5a3b+2c)
= a4b2c5a+3b2c
= a5a4b+3b2c2c
= 4ab4c
Question 9. A number is decreased by 15 and the new number so obtained is multiplied by 3; the result is 81. Find the number. [3 MARKS]
 Discuss Question

:
Equation: 1 Mark
Steps: 1 Mark
Answer: 1 Mark
Let the number be x.
The number decreased by 15 (x15)
The number so obtained is multip[lied by 33×(x15)
Given: 3(x15)=813x45=81
3x=81+45
x=1263=42
The required number = 42
Question 10. The equation 5t - 4 = 1 is satisfied when the value of t = 1.
  1.    True
  2.    False
 Discuss Question
Answer: Option A. -> True
:
A
In order to check whether the above equation 5t-4 =1 is satisfied for t =1, we simply put 1 in place of t, So substituting t = 1 in the equation , we get
LHS = 5× (1)- 4 =1 andRHS = 1.
Since, LHS=RHS,t =1 satisfies the equation 5t-4 =1.

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