Sail E0 Webinar

11th And 12th > Chemistry

ALDEHYDES AND KETONES MCQs

Total Questions : 30 | Page 1 of 3 pages
Question 1.


Identify Z in the series, CH3CHOMnO4−−−−−Dil.H2SO4 X SOCl2−−− Y CH3COONa−−−−−−−Heat Z:


  1.     CH3.CO.CH2COONa
  2.     (CH3CO)2O
  3.     CH2Cl.CO.O.COCH3
  4.     CHCl2.CO.O.COCH3
 Discuss Question
Answer: Option B. -> (CH3CO)2O
:
B

H3CCHO MnO4−−−−dil.H2SO4 H3CCOOH SOCl2−−−H3CCOCl CH3COONa−−−−−−−Identify Z In The Series, CH3CHOMnO−4−−−−−−→...


Question 2.


A compound A has molecular formula C2Cl3OH. It reduces Fehling’s solution and on oxidation gives a monocarboxylic acid B. A is obtained by action of Cl2 on ethyl alcohol. A is:


  1.     chloral
  2.     CHCl3
  3.     CH3Cl
  4.     chloro acetic acid
 Discuss Question
Answer: Option A. -> chloral
:
A

A Compound A Has Molecular Formula C2Cl3OH. It Reduces Fehli...


Chlorine reduces Fehling’s solution due to the aldehyde group that converts to  COOH group 


Question 3.


The increasing order of the rate of HCN addition to compounds A-D is:


(A) HCHO (B) CH3COCH3


(C) PhCOCH3 (D) PhCOPh


  1.     A<B<C<D
  2.     D<B<C<A
  3.     D<C<B<A
  4.     C<D<B<A
 Discuss Question
Answer: Option C. -> D<C<B<A
:
C

Due to steric hindrance


Question 4.


The correct order of acid strength is:


  1.     CH3COOH>CH2ClCOOH>CHCl2COOH
  2.     CHCl2COOH>CH2ClCOOH>CH3COOH
  3.     CHCl2COOH>CH3COOH>CH2ClCOOH
  4.     CH2ClCOOH>CH3COOH>CHCl2COOH
 Discuss Question
Answer: Option B. -> CHCl2COOH>CH2ClCOOH>CH3COOH
:
B

Greater the number of –I groups on the α-carbon, acidic nature increases .


Question 5.


A ketone reacted with C2H5MgBr reagent followed by hydrolysis gave a product which on dehydration gives an alkene. The alkene on ozonolysis gave diethyl ketone and acetaldehyde. The ketone is:


  1.     dimethyl ketone
  2.     ethyl methyl ketone
  3.     diethyl ketone
  4.     ethyl propyl ketone
 Discuss Question
Answer: Option C. -> diethyl ketone
:
C

A Ketone Reacted With C2H5MgBr Reagent Followed By Hydrolysi...


Question 6.


CH3CHO+CH2(COOH)2△−−−−→PyridineX; X Is :CH3CHO+CH2(COOH)2−−−PyridineX; X is :


  1.     CH3COOH
  2.     C2H5COOH
  3.     CH3CHCHCOOH
  4.     (COOH)CHCH(COOH)
 Discuss Question
Answer: Option C. -> CH3CHCHCOOH
:
C

CH3CHO+CH2(COOH)2△−−−−→PyridineX; X Is :


Question 7.


CH3CHO+H2NOHCH3CH=NOH The above reaction occurs at:


  1.     pH = 1 
  2.     pH = 4.5
  3.     any value of pH
  4.     pH = 12
 Discuss Question
Answer: Option B. -> pH = 4.5
:
B

In highly acidic medium, NH2OH forms salt with the acid molecules and loses its ability to act as a nucloephile.


Question 8.


In a set of reactions propionic acid yielded a compound D. CH3CH2COOHSOCl2−−−BNH3−−CKOH−−Br2D The structure of D would be:


  1.     CH3CH2NHCH3
  2.     CH3CH2NH2
  3.     CH3CH2CH2NH2
  4.     CH3CH2CONH2
 Discuss Question
Answer: Option B. -> CH3CH2NH2
:
B

In A Set Of Reactions Propionic Acid Yielded A Compound D. C...


Question 9.


Identify the correct order of boiling points of the following compounds.


1. CH3(CH2)2CH2OH
2. CH3(CH2)2CHO
3. CH3(CH2)2COOH
  1.     1>2>3
  2.     3>1>2
  3.     1>3>2
  4.     3>2>1
 Discuss Question
Answer: Option B. -> 3>1>2
:
B

Greater the tendency for h-bonding, higher is the B.P.


Question 10.


CH3COOEt CH3MgBr−−−−−ExcessP


  1.    
  2.    
  3.    
  4.    
 Discuss Question
Answer: Option A. ->
:
A

CH3COOEt CH3MgBr−−−−−−→ExcessP


Latest Videos

Latest Test Papers