Question
#include<stdio.h>
int i;
int fun();
int main()
{
while(i)
{
fun();
main();
}
printf("Hello\n");
return 0;
}
int fun()
{
printf("Hi");
}
What will be the output of the program?
#include<stdio.h>
int i;
int fun();
int main()
{
while(i)
{
fun();
main();
}
printf("Hello\n");
return 0;
}
int fun()
{
printf("Hi");
}
Answer: Option A
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Step 1: int i; The variable i is declared as an integer type.
Step 1: int fun(); This prototype tells the compiler that the function fun() does not accept any arguments and it returns an integer value.
Step 1: while(i) The value of i is not initialized so this while condition is failed. So, it does not execute the while block.
Step 1: printf("Hellon"); It prints "Hello".
Hence the output of the program is "Hello".
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