Question
#include<stdio.h>
int main()
{
char p[] = "%d\n";
p[1] = 'c';
printf(p, 65);
return 0;
}
What will be the output of the program ?
#include<stdio.h>
int main()
{
char p[] = "%d\n";
p[1] = 'c';
printf(p, 65);
return 0;
}
Answer: Option A
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Step 1: char p[] = "%d`setminus`n"; The variable p is declared as an array of characters and
initialized with string "%d".
Step 2: p[1] = 'c'; Here, we overwrite the second element of array p by 'c'. So array
p becomes "%c".
Step 3: printf(p, 65); becomes printf("%c", 65);
Therefore it prints the ASCII value of 65. The output is 'A'.
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