Question
#include<stdio.h>
int main()
{
const int i=0;
printf("%d\n", i++);
return 0;
}
What will be the output of the program?
#include<stdio.h>
int main()
{
const int i=0;
printf("%d\n", i++);
return 0;
}
Answer: Option D
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This program will show an error "Cannot modify a const object".
Step 1: const int i=0; The constant variable 'i' is declared as an integer and initialized with value
of '0'(zero).
Step 2: printf("%dn", i++); Here the variable 'i' is increemented by 1(one). This will create an error
"Cannot modify a const object".
Because, we cannot modify a const variable.
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