Question
#include<stdio.h>
int main()
{
const char *s = "";
char str[] = "Hello";
s = str;
while(*s)
printf("%c", *s++);
return 0;
}
What will be the output of the program?
#include<stdio.h>
int main()
{
const char *s = "";
char str[] = "Hello";
s = str;
while(*s)
printf("%c", *s++);
return 0;
}
Answer: Option C
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Step 1: const char *s = ""; The constant variable s is declared as an pointer to an array of
characters type and initialized with an empty string.
Step 2: char str[] = "Hello"; The variable str is declared as an array of charactrers type and
initialized with a string "Hello".
Step 3: s = str; The value of the variable str is assigned to the variable s. Therefore strcontains
the text "Hello".
Step 4: while(*s){ printf("%c", *s++); } Here the while loop got executed untill the value of the
variable s is available and it prints the each character of the variable s. and it prints the each
character of the variable s.
Hence the output of the program is "Hello".
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