Question
#include<stdio.h>
int main()
{
int y=128;
const int x=y;
printf("%d\n", x);
return 0;
}
What will be the output of the program?
#include<stdio.h>
int main()
{
int y=128;
const int x=y;
printf("%d\n", x);
return 0;
}
Answer: Option A
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Step 1: int y=128; The variable 'y' is declared as an integer type and initialized to value "128".
Step 2: const int x=y; The constant variable 'x' is declared as an integer and it is initialized with the variable 'y' value.
Step 3: printf("%dn", x); It prints the value of variable 'x'.
Hence the output of the program is "128"
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