Question
class s1 implements Runnable
{
int x = 0, y = 0;
int addX() {x++; return x;}
int addY() {y++; return y;}
public void run() {
for(int i = 0; i < 10; i++)
System.out.println(addX() + " " + addY());
}
public static void main(String args[])
{
s1 run1 = new s1();
s1 run2 = new s1();
Thread t1 = new Thread(run1);
Thread t2 = new Thread(run2);
t1.start();
t2.start();
}
}
What will be the output of the program?
class s1 implements Runnable
{
int x = 0, y = 0;
int addX() {x++; return x;}
int addY() {y++; return y;}
public void run() {
for(int i = 0; i < 10; i++)
System.out.println(addX() + " " + addY());
}
public static void main(String args[])
{
s1 run1 = new s1();
s1 run2 = new s1();
Thread t1 = new Thread(run1);
Thread t2 = new Thread(run2);
t1.start();
t2.start();
}
}
Answer: Option C
public void run()
{
for(int i = 0; i < 10; i++)
System.out.println(
Thread.currentThread().getName() + ": " + addX() + " " + addY()
);
}
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Both threads are operating on different sets of instance variables. If you modify the
code of the run() method to print the thread name it will help to clarify the output:
public void run()
{
for(int i = 0; i < 10; i++)
System.out.println(
Thread.currentThread().getName() + ": " + addX() + " " + addY()
);
}
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