Question
class PassS
{
public static void main(String [] args)
{
PassS p = new PassS();
p.start();
}
void start()
{
String s1 = "slip";
String s2 = fix(s1);
System.out.println(s1 + " " + s2);
}
String fix(String s1)
{
s1 = s1 + "stream";
System.out.print(s1 + " ");
return "stream";
}
}
What will be the output of the program?
class PassS
{
public static void main(String [] args)
{
PassS p = new PassS();
p.start();
}
void start()
{
String s1 = "slip";
String s2 = fix(s1);
System.out.println(s1 + " " + s2);
}
String fix(String s1)
{
s1 = s1 + "stream";
System.out.print(s1 + " ");
return "stream";
}
}
Answer: Option D
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When the fix() method is first entered, start()'s s1 and fix()'s s1 reference variables both
refer to the same String object (with a value of "slip"). Fix()'s s1 is reassigned to a new
object that is created when the concatenation occurs (this second String object has a
value of "slipstream"). When the program returns to start(), another String object is created,
referred to by s2 and with a value of "stream".
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